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NARA [144]
3 years ago
5

Which graph represents the solution to this system of inequalities? y ≤ -2x y > 3x − 4

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
3 0

Answer:

Option A,

Only that graph represents the solution to the given system of inequalities.

Answered by GAUTHMATH

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Thomas paid a one-time registration
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Answer:

There is no error

Step-by-step explanation:

He stated with 15 15x and made 10 for each y=15+10

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3 years ago
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What are the zeros of f(x) = x2 + x - 20?
jeyben [28]

Answer:

x = - 5, x = 4

Step-by-step explanation:

Given

f(x) = x² + x - 20

To find the zeros equate f(x) to zero, that is

x² + x - 20 = 0

Consider the factors of the constant term ( - 20) which sum to give the coefficient of the x- term ( + 1)

The factors are + 5 and - 4, since

5 × - 4 = - 20 and + 5 - 4 = + 1, hence

(x + 5)x - 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

x - 4 = 0 ⇒ x = 4

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3 years ago
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Answer:

Step-by-step explanation:Worked out on paper shown below

Also I recommended a online app called (it has wierd name but it’s helpful for algebra) mathpapa

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2 years ago
When graphing a linear inequality, when can you NOT use (0, 0) as a test point to determine which side of a boundary line to sha
TEA [102]
When the point (0,0) is on the boundary line
8 0
3 years ago
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HELP When 2((Three-fifths x + 2 and three-fourths y minus one-fourth x minus 1 and one-half y + 3)) is simplified, what is the r
lesya692 [45]

Answer:

<h2> StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6</h2>

Step-by-step explanation:

Given the expression 2(\frac{3x}{5}+2\frac{3y}{4}-\frac{x}{4}-1 \frac{1}{2}y+3)

To simplify the expression, we need to first collect the like terms of the functions in parentheses as shown;

= 2(\frac{3x}{5}-\frac{x}{4}-1 \frac{1}{2}y+2\frac{3}{4}y+3)\\= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\

Then we find the LCM of the resulting function

= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\= 2(\frac{12x-5x}{20} - (\frac{6y-11y}{4})+3)\\= 2(\frac{7x}{20}- (\frac{-5y}{4})+3 )\\= 2(\frac{7x}{20}+ \frac{5y}{4}+3 )\\= \frac{7x}{10} + \frac{5y}{2} +6\\=  \frac{7x}{10} + 2\frac{1}{2}y+6\\

The final expression gives the required answer

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3 years ago
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