Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and 
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To find:
The 
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Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]
In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
The base angles of an isosceles triangle are congruent. So,
[Base angles of an isosceles triangle]
Using the angle sum property in triangle AOB, we get
Hence, the measure of angle AOB is 120 degrees.
The interior and exterior triangles are related because they are in the pyramid x + c = Triangle so thats how
Answer: 16 square units
Step-by-step explanation:
let the vertex in quadrant I be (x,y)
then the vertex in quadratnt II is (-x,y)
base of the rectangle = 2x
height of the rectangle = y
Area = xy
= x(12 - x²)
= -x³ + 12x
d(area)/dx = 3x² - 12 = 0 for a maximum of area
3x² = 12
x² = 4
x = ±2
y = 12-4 = 8
So, the largest area = 2 x 8 = 16 square units
Numbers that are close in value to the actual numbers.
7, 14 would be it but you have to divide the whole equation by 2 to get the y alone
