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guapka [62]
2 years ago
7

Use these sentence starters to explain how Cat Insanity is an analogy for debt repayment.

Computers and Technology
1 answer:
denpristay [2]2 years ago
7 0

Answer: Can Insanity is like a debt repayment, if you don't pay or feed it on time they will die/ interest rate of the bank will be more and more expensive.

Explanation:

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Which type of inventory control is expensive but helps keep inventory especially secure? A. RFID tags B. Barcodes C. Visual merc
lawyer [7]

Answer:

a) RFID tags

Explanation:

yeah they're super expensive but keep everything secure so nothing gets in it .

3 0
2 years ago
How do operating system work?
SIZIF [17.4K]

Answer:

The "operating system" manages software and hardware on the computer. Uploads files, has great memory and processes management.

7 0
2 years ago
Consider the following code segment.
mafiozo [28]

Answer:

for (int h = k; h >= 0; h--)

Explanation:

From the list of given options, option C answers the question.

In the outer loop

Initially, k = 0

In the inner loop,

h = k = 0

The value of h will be printed once because h>=0  means 0>=0 and this implies once

To the outer loop

k = 1

The inner loop will always assume value of k;

So,

h = 1

This will be printed twice because of the condition h>=0  means 1>=0.

Since 1 and 0 are >=0; 1 will be printed twice

To the outer loop

k = 2

The inner loop

h = 2

This will be printed thrice because of the condition h>=0  means 2>=0.

Since 2, 1 and 0 are >=0; 2 will be printed thrice

To the outer loop

k = 3

The inner loop

h = 3

This will be printed four times because of the condition h>=0  means 3>=0.

Since 3, 2, 1 and 0 are >=0; 3 will be printed four times

7 0
3 years ago
Consider a company that needs to sort an array of structures of type Customer by balance, with the largest balance first. Here i
8090 [49]

Answer:

#include <iostream>

#include <string>

#include <cstring>

#include <cstdlib>

using namespace std;

struct Person

{

string name;

int age;

};

int main()

{

struct Person data[10];

struct Person *pData[10],*temp;

string names[] = {"a","b","c","g","z","l","p","q","r","w"};

int num[] = {4,6,34,8,13,90,33,22,18,23};

for(int i=0;i<9;i++)

{

data[i].name = names[i];

data[i].age = num[i];

pData[i] = &data[i];

}

for(int i=0;i<9;i++)

{

for(int j=i+1;j<9;j++)

{

if(pData[i]->name.compare(pData[j]->name)>0)

{

temp = pData[i];

pData[i] = pData[j];

pData[j] = temp;

}

}

}

for(int i=0;i<9;i++)

{

cout<<pData[i]->name<<" "<<pData[i]->age<<endl;

}

}

Explanation:

The line #include <iostream> initializes the program.

This program created an array of only 10 structures, Customer data. Also defined an auxiliary array Customer *pData.

The program uses these parameters to sorts the array of pointers so that when you go through pData in increasing order of index k, the entries pData[k] point to Customer objects in decreasing order by balance, meaning that pdata[0] now points to the customer with the highest balance, and pData[9] points to the customer with the smallest balance.

4 0
2 years ago
The first step when entering data is _
34kurt

Answer:

click on the cell

Explanation:

This is a little tricky. We need to first think of the column, then of row, and then click on the corresponding cell. And then we either start typing or move our mouse to highlight the cells. Hence, the correct option here is click on the cell.

3 0
3 years ago
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