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Tamiku [17]
2 years ago
7

Which type of inventory control is expensive but helps keep inventory especially secure? A. RFID tags B. Barcodes C. Visual merc

handising D. CRM software Please select the best answer from the choices provided A B C D.
Computers and Technology
1 answer:
lawyer [7]2 years ago
3 0

Answer:

a) RFID tags

Explanation:

yeah they're super expensive but keep everything secure so nothing gets in it .

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In 1972, earlier designers built the
Sonbull [250]

The exercise is about filling in the gaps and is related to the History of the ARPANET.

<h3>What is the History of the ARPANET?</h3>

From the text:

In 1972, earlier designers built the <u>ARPANET </u>connecting major universities. They broke communication into smaller chunks, or <u>packets </u>and sent them on a first-come, first-serve basis. The limit to the number of bytes of data that can be moved is called line capacity, or <u>bandwidth</u>.

When a network is met its capacity the user experiences <u>unwanted pauses</u>. When the network is "slowing down", what is happening is users are waiting for their packet to leave the <u>queue</u>.

To make the queues smaller, developers created <u>mixed </u>packets to move <u>simultaneously</u>.

Learn more about the ARPANET at:
brainly.com/question/16433876

7 0
2 years ago
If you were the IT manager for a large manufacturing company,what issues might you have with the use of opensource software? Wha
Rzqust [24]

Answer: Having the ability to change the source code to fit your needs

Explanation:

7 0
3 years ago
Programming challenge description: Given a string comprising just of the characters (,),{,},[,] determine if it is well-formed o
nadezda [96]

Answer:

Employing Java language,

Explanation:

//for using stack data structure

import java.util.Stack;

//class definition

public class BracketMatch {

   //function to find the string is well formed or not

   public static boolean isWellFormed(String str) {

       //variable to store the character value

       char ch;

       //check if the first character itself is the end of the brackets

       if (str.charAt(0) == ')'||str.charAt(0) =='}'||str.charAt(0) ==']')

           return false;

       //creating a stack of character type

       Stack<Character> stack = new Stack<Character>();

       //iterating through the characters in string

       for(int i=0; i < str.length(); i++) {

           //storing the current character from the string in the variable

           ch = str.charAt(i);

           if(ch == '('||ch=='{'||ch=='[')

               //if the character is starting of the brackets push it into stack

               stack.push(ch);

           else if(ch == ')')

               //if it is closing bracket and the stack is empty then the string is not well formatted

               if(stack.empty())

                   return false;

               else if(stack.peek() == '(')

                   stack.pop();

               else

                   return false;

           else if(ch == '}')

               if(stack.empty())

                   return false;

               else if(stack.peek() == '{')

                   stack.pop();

               else

                   return false;

       }

       //returning the stack content, if the string will be well formed the stack would be empty

       //after all the operations

       return stack.empty();

   }

   //main method

   public static void main(String[] args) {

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("{}"));

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("([)]"));

   }

}

5 0
4 years ago
"assignment is to create a program that will read a value from an array, and then place this value in another array with the loc
White raven [17]

Answer:

#include <iostream>//including libraries

using namespace std;

int main()

{

int arr[6] = { 0,1,2,3,4,5 };//make sure size of arr is 1 less than secArr

int secArr[7];//second array (1 element bigger)

for (int i = 0;i < 6;i++)//looping through each element (6 times)

{

 secArr[i + 1] = arr[i];//transferring elements to second array and shifting by 1 cell

 cout << secArr[i + 1] << endl;//printing elements of second array

}

return 0;//terminating program

}

Explanation:

The array size can range from any number. just make sure to keep arr one less than secArr. This is because we need the room for the extra element. This task is to help you understand how array work and how to parse through them using loops. For loops are the best for this task because even if you think intuitively, they work for as long as there are items in the array. and you can define the size yourself.

5 0
3 years ago
Identfy two duties of the governer stationed at mombasa under portugues rule?​
Tpy6a [65]

Answer:I got u

Explanation:

6 0
3 years ago
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