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quester [9]
3 years ago
10

Which statement correctly describes how a bar magnet should be placed on a globe to correctly align with Earth's magnetic field?

Physics
2 answers:
tatyana61 [14]3 years ago
7 0

Answer: C. Place the magnet vertically on the equator with the north end facing the North pole.

Explanation: A P E X

Dima020 [189]3 years ago
5 0
The answer is B. When the magnet is placed on a globe to correctly align with Earth’s magnetic field, it is considered to be suspended freely. The Earth has geographical poles as well with North and South poles. Since unlike poles attract, the South Pole of the magnet will be attracted to the geographical North.
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A single conservative force acts on a 5.30-kg particle within a system due to its interaction with the rest of the system. The e
cupoosta [38]

Answer:

Given that

m = 5.3 kg

Fx = 2x + 4

We know that work done by force F given as

w= ∫ F. dx

a)

Given that x=1.08 m to x=6.5 m

Fx = 2x + 4

w= ∫ F. dx

w=\int_{1.08}^{6.5}(2x+4) .dx

w=\left [x^2+4x \right ]_{1.08}^{6.5}

w=(6.5^2-1.08^2)+4(6.5-1.08)\ J

w=62.7 J

b)

We know that potential energy given as

F=-\dfrac{dU}{dx}

∫ dU =  -∫F.dx           ( w= ∫ F. dx)

ΔU= -62.7 J

c)

We know that form work power energy theorem

Net work = Change in kinetic energy

W= KE₂ - KE₁

62.7 =KE₂ - (1/2)x 5.3 x 3²

KE₂ = 86.55 J

This is the kinetic energy at 6.5m

8 0
3 years ago
A runner runs a 5k race (3.1 miles) at a rate of 6.7
4vir4ik [10]

Answer:monkey

Explanation:

5 0
4 years ago
You should check your battery ___________.
podryga [215]

One should check the battery every week.

A battery if not maintained properly can cause it to die earlier or get damaged. The reasons why should the battery be checked regularly is that due to improper management of the battery and also the weather conditions, the battery usually gets corroded easily and the battery won't be able to work properly.

The connections must be checked properly so that the battery gets charged properly and should not die while driving.

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Read 2 more answers
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3 years ago
Situation A bichromatic source produces light having wavelengths in vacuum of 450 nm and 650 nm. The indices of refraction are 1
erica [24]

Answer:

\theta=0.52^{\circ}

Explanation:

It is given that,

Wavelength in vacuum, \lambda_1=450\ nm

Wavelength in vacuum, \lambda_2=650\ nm

Refractive index for air, n_1=1

First refractive index, n =1.44

Second refractive index, n' =1.42

A ray is incident at an angle of incidence of 50 degrees. Let r is the angle of refraction. Firstly calculating the angle of refraction for two values of wavelength from Snell's law as :

\dfrac{sin\ i}{sin\ r}=\dfrac{n_2}{n_1}

r=sin^{-1}(\dfrac{n_1\ sin\ i}{n})

For 450 nm, r=sin^{-1}(\dfrac{1\ sin(50)}{1.44})

r = 32.13 degrees

For 650 nm, r'=sin^{-1}(\dfrac{1\ sin(50)}{1.42})

r' = 32.65 degrees

Let \theta is the angle of dispersion between the two refracted rays in the oil such that,

\theta=r'-r

\theta=32.65-32.13

\theta=0.52^{\circ}

So, the angle of dispersion between the two refracted rays in the oil is closest to 0.52 degrees.

3 0
3 years ago
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