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nirvana33 [79]
3 years ago
13

You should check your battery ___________.

Physics
2 answers:
NNADVOKAT [17]3 years ago
8 0

<u>The battery should be checked </u><u>every six month</u><u> to ensure that it is working properly.</u>

Explanation:

The battery is the power source for the car as it provides power for several functions that are going in the car. The battery used in a car is always in use whenever the car is driven.

The battery used in a car should be checked for any malfunctioning as it may cause harm to it. The battery may be dead earlier than its life if it is not been taken care at regular intervals.

So, in order to keep the battery of the car working properly, it should be ensured that the battery is checked every five-six month or at least twice in a year. This way, if there is any malfunctioning in any part of it, it can be detected and can be made correct in appropriate time.

Thus, <u>The battery should be checked </u><u>every six month</u><u> to ensure that it is working properly.</u>

<u />

Learn More:

1. Compare the types of friction brainly.com/question/1800116

2. Fossil which is formed when the outline of original organism is formed brainly.com/question/2856442

3. Why does the refraction of light takes place brainly.com/question/3095091

Answer Details:

Grade: Middle School

Subject: Physics

Chapter: Battery

Keywords:

Every six month, every week, car, battery, malfunctioning, detected, appropriate, power source, driving.

podryga [215]3 years ago
5 0

One should check the battery every week.

A battery if not maintained properly can cause it to die earlier or get damaged. The reasons why should the battery be checked regularly is that due to improper management of the battery and also the weather conditions, the battery usually gets corroded easily and the battery won't be able to work properly.

The connections must be checked properly so that the battery gets charged properly and should not die while driving.

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Find electric field at point p which is a distance l away from the both +q and -q
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Answer:

\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

Explanation:

As given point p is equidistant from both the charges

It must be in the middle of both the charges

Assuming all 3 points lie on the same line

Electric Field due a charge q at a point ,distance r away

=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{r^{2} }

Where

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  • r is the distance
  • E is the permittivity of medium

Let electric field due to charge q be F1 and -q be F2

I is the distance of P from q and also from charge -q

⇒

F1=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }

F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

⇒

F1+F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

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