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nirvana33 [79]
3 years ago
13

You should check your battery ___________.

Physics
2 answers:
NNADVOKAT [17]3 years ago
8 0

<u>The battery should be checked </u><u>every six month</u><u> to ensure that it is working properly.</u>

Explanation:

The battery is the power source for the car as it provides power for several functions that are going in the car. The battery used in a car is always in use whenever the car is driven.

The battery used in a car should be checked for any malfunctioning as it may cause harm to it. The battery may be dead earlier than its life if it is not been taken care at regular intervals.

So, in order to keep the battery of the car working properly, it should be ensured that the battery is checked every five-six month or at least twice in a year. This way, if there is any malfunctioning in any part of it, it can be detected and can be made correct in appropriate time.

Thus, <u>The battery should be checked </u><u>every six month</u><u> to ensure that it is working properly.</u>

<u />

Learn More:

1. Compare the types of friction brainly.com/question/1800116

2. Fossil which is formed when the outline of original organism is formed brainly.com/question/2856442

3. Why does the refraction of light takes place brainly.com/question/3095091

Answer Details:

Grade: Middle School

Subject: Physics

Chapter: Battery

Keywords:

Every six month, every week, car, battery, malfunctioning, detected, appropriate, power source, driving.

podryga [215]3 years ago
5 0

One should check the battery every week.

A battery if not maintained properly can cause it to die earlier or get damaged. The reasons why should the battery be checked regularly is that due to improper management of the battery and also the weather conditions, the battery usually gets corroded easily and the battery won't be able to work properly.

The connections must be checked properly so that the battery gets charged properly and should not die while driving.

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Consider, please, this solution:

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All the details are in the attachment.

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3 years ago
Let's take two balls, each of radius 0.1 meters and charge them each to 3 microCoulombs. Then, let's put them on a flat surface
salantis [7]

Explanation:

First, we will calculate the electric potential energy of two charges at a distance R as follows.

                   R = 2r

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                      = 0.2 m

where,    R = separation between center's of both Q's. Hence, the potential energy will be calculated as follows.

                U = \frac{k \times Q \times Q}{R}

                    = \frac{8.98 \times 10^{9} \times (3 \times 10^{-6} C)^{2}}{0.1}

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As, both the charges are coming towards each other with the same energy so there will occur equal sharing of electric potential energy between these two charges.

Therefore, when these charges touch each other then they used to posses maximum kinetic energy, that is, \frac{U}{2}.

Hence,   K.E = \frac{U}{2}

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Now, we will calculate the speed of balls as follows.

                 V = \sqrt{\sqrt{\frac{2 \times K.E}{m}}

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Therefore, we can conclude that final speed of one of the balls is 0.142 m/s.

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A 2.4-kg ball falling vertically hits the floor with a speed of 2.5 m/s and rebounds with a speed of 1.5 m/s. What is the magnit
gayaneshka [121]

Answer:

9.6 Ns

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Where I = impulse, m = mass of the ball, v = final velocity, u = initial velocity.

Given: m = 2.4 kg, v = 2.5 m/s, u = -1.5 m/s (rebounds)

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