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padilas [110]
3 years ago
11

14. A polygon ABCD is inscribed in a circle. Find angle ABC

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
7 0

Answer:

m<ABC = 100degrees

m<IJG = 104degrees

Step-by-step explanation:

14. The sum of the opposite angle of the quadrilateral is 180degrees. Hence;

m<ADC + m<ABC = 180

3y+8+4y+4 = 180

7y + 12 = 180

7y = 180 - 12

7y = 168

y = 168/7

y = 24

Get <ABC

m<ABC  = 4y+4

m<ABC = 4(24) + 4

m<ABC = 96 + 4

m<ABC = 100degrees

15. Similarly for this;

GHI + IJG = 180

76 + m<IJG = 180

m<IJG = 180 - 76

m<IJG = 104degrees

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Answer and Step-by-step explanation:

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3 years ago
Read 2 more answers
Mal spends 7 hours in school each day. Her lunch period is 1 hour long, and she spends a
Alex787 [66]

Answer:

z = 5*(1/2)

z = 5/10

---

time switching classes:

w = 7/10

---

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (76/10 - 5/10 - 7/10)/6

x = (76 - 5 - 7)/(10*6)

x = (64)/(10*6)

x = (2*2*2*2*2*2)/(2*5*2*3)

x = (2*2*2*2)/(5*3)

x = 16/15

x = 1.0666666666

---

check:

y = 7 + 3/5

y = 7.6

z = 1/2

z = 0.5

w = 7/10

w = 0.7

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (7.6 - 0.5 - 0.7)/6

x = 1.0666666666

---

answer:

z = 5*(1/2)

z = 5/10

---

time switching classes:

w = 7/10

---

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (76/10 - 5/10 - 7/10)/6

x = (76 - 5 - 7)/(10*6)

x = (64)/(10*6)

x = (2*2*2*2*2*2)/(2*5*2*3)

x = (2*2*2*2)/(5*3)

x = 16/15

x = 1.0666666666

---

check:

y = 7 + 3/5

y = 7.6

z = 1/2

z = 0.5

w = 7/10

w = 0.7

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (7.6 - 0.5 - 0.7)/6

x = 1.0666666666

---

answer:

each class is 1.07 hours

Step-by-step explanation:

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