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2 years ago

13

The actual width of the building shown in the model below is 60 feet: What is the actual height od the building shown in the mod

el?
100ft
150ft
210ft
300ft

the building shows the height as 5 and width is 2...

1 answer:

Murrr4er [49]2 years ago

8 0

Answer:

100ft I'm not completely sure but

Step-by-step explanaon 5x5=25 2x2=4 25x4=100

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If you can help please do! Thank you!

Aleks [24]

Answer:

see explanation

Step-by-step explanation:

The diagonals of a parallelogram bisect each other , then

CO = OA = b

DO = OB = a

(a)

CA = CO + OA = b + b = 2b

(b)

DC = DO + OC = a - b

(c)

CB = CO + OB = b + a = a + b

7 0

2 years ago

Find the area and the circumference of the circle. Round your answers to the nearest hundredth.

Alik [6]

Answer:

$area = 200.96 \: {units}^{2} \\ circumfrence = 50.24 \: units$

Step-by-step explanation:

The formula to find the area and circumference of a circle is:

$area = \pi {r}^{2} \\ circumfrence = 2\pi \: r$

<em>*</em><em>no</em><em>te that pi is 3.14*</em><em> </em>Therefore the area is:

$formula = \pi {r}^{2} \\ 3.14 \times {8}^{2} = \\ 3.14 \times 64 = 200.96$

Therefore the circumference is:

$formula = \: 2\pi \: r \\ (2)(3.14)(8) = \\ 3.14 \times 16 = 50.24$

3 0

2 years ago

Math help please show work

Step2247 [10]

Answer:

the jam requires three qts of raspberry so that would be 12 cups and there are 2 cups to a pint so 6 pints I think

8 0

3 years ago

Read 2 more answers

The most efficient first step in the process to factor the trinomial is :

yaroslaw [1]

<span>On every type of factoring problem ALWAYS look first for a GCF, a greatest common factor. </span>

5 0

3 years ago

Please help me prove that ED is congruent to BA! I thought I had it right by proving right and vertical angles, but I’m missing

Vikki [24]

Step-by-step explanation:

$\overline{DA} \text{ bisects } \overline{EB}$ is given

$\overline{BC} \cong \overline{EC}$ definition of <u>bisect</u>

<u /> $\overline{EB} \perp \overline{ED}, \, \overline{EB} \perp \overline{BA}$ are both given

<u /> $\angle B, \, \angle E \text{ are right angles}$ definition of perpendicular

$\angle B \cong \angle E$ because all right angles are congruent

$\angle{ACB} \cong \angle{DCE}$ vertical angles are congruent

$\triangle{ACB} \cong \triangle{DCE}$ ASA (angle-side-angle)

$\overline{ED} \cong \overline{BA}$ CPCTC (corresponding parts of congruent triangles are congruent)

5 0

2 years ago