Question

a partical moves horizontally in a uniform circular motion ,over a horizontal xy plane .At one instant ,it moves through the point at coordintate (4m , 4m) with a velocity of -5.0i m/s and an acceleration of +12.5j m/s(sqr) . what is the (a)x and (b) y coordinates of the center of the circular path?

Answer 1

R  = V^2/a

= 5^2 /12.5

= 2

the y coordinate would be : 2 + 4 = 6m

Hope this helps