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horrorfan [7]
3 years ago
8

a partical moves horizontally in a uniform circular motion ,over a horizontal xy plane .At one instant ,it moves through the poi

nt at coordintate (4m , 4m) with a velocity of -5.0i m/s and an acceleration of +12.5j m/s(sqr) . what is the (a)x and (b) y coordinates of the center of the circular path?
Mathematics
1 answer:
Inessa [10]3 years ago
8 0
R  = V^2/a

= 5^2 /12.5

= 2

the y coordinate would be : 2 + 4 = 6m

Hope this helps
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