Answer:
Q1 = 7.25*10^(-16) C
Explanation:
We are given;
electric field strength = (1 x 10^5 N/C
drag force (F) = 7.25 x 10^(-11) N
The question says it's moving with constant velocity. This means that he particle is in equilibrium and not accelerating.
Columbs law force of attraction or repulsion between two charges is given as;
F=(KQ1Q2)/r²
Now, electric field strength is given as the formula;(K*Q2)/r², thus plugging the relevant values gives us;
7.25 x 10^(-11) N= (1 x 10^(5) N/C)Q1 Q1 = 7.25 x 10^(-11) /(1 x 10^(5))
Q1 = 7.25*10^(-16) C
When a candle is burning and
wind is blowing it on one side of the flame, which causes the flame to bend
towards the wind is an example of Bernoulli’s principle. The principle explain
that the higher the speed,
the lower the pressure becomes. When you blow against one side of the flame, you are creating
an area of low pressure. The relatively high-pressure air on the other side of
the candle will rush over to fill the area of low pressure that causes the flame to be
pushed in the direction of the blowing.
They did not believed Galileo's discoveries because religiouse reasons the preast said that all the bible is true but Galileo despised it.
Answer:
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