<span>the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch</span>
Compute the work done on the table:
<em>W</em> = <em>Fd</em> = (320 N) (32 m) = 10,240 J
Divide this by the given time duration to get the power output:
<em>P</em> = <em>W</em>/∆<em>t</em> = (10,240 J) / (150 s) ≈ 63.3 W
Answer:
it has 3 electrons. brainliest please
Answer:
11.09 m/s
Explanation:
Given that an object is thrown vertically up and attains an upward velocity of 9.6 m/s when it reaches one fourth of its maximum height above its launch point.
The parameters given are:
Initial velocity U = ?
Final velocity V = 9.6 m/s
Acceleration due to gravity g = 9.8m/s^2
Let first assume that the object is thrown from rest with the velocity U, at maximum height V = 0
Using third equation of motion
V^2 = U^2 - 2gH
0 = U^2 - 2 × 9.8H
U^2 = 19.6H ........ (1)
Using the formula again for one fourth of its maximum height
9.6^2 = U^2 - 2 × 9.8 × H/4
92.16 = U^2 - 19.6/4H
92.16 = U^2 - 4.9H
U^2 = 92.16 + 4.9H ...... (2)
Substitute U^2 in equation (1) into equation (2)
19.6H = 92.16 + 4.9H
Collect the like terms
19.6H - 4.9H = 92.16
14.7H = 92.16
H = 92.16/14.7
H = 6.269
Substitute H into equation 2
U^2 = 92.16 + 4.9( 6.269)
U^2 = 92.16 + 30.72
U^2 = 122.88
U = 11.09 m/s
Therefore, the initial velocity of the object is 11.09 m/s
40kg
Explanation:
Given parameters:
Kinetic energy = 500J
Velocity = 5m/s
Unknown:
Mass of the object = ?
Solution:
Kinetic energy is the energy due to motion of a body. It is expressed as:
K.E = 
mv²
m is the mass of the body
v is the velocity
To find the mass, make it the subject of the expression:
m = ![\frac{2 K.E}{v[tex]^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B2%20K.E%7D%7Bv%5Btex%5D%5E%7B2%7D)
}[/tex]
m = ![\frac{2 x 500}{5[tex]^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B2%20x%20500%7D%7B5%5Btex%5D%5E%7B2%7D)
}[/tex] = 40kg
Learn more:
Kinetic energy brainly.com/question/6536722
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