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suter [353]
3 years ago
14

1. (15 points) Small cart is rolling down an inclined track and accelerating. It fires a ball straight out of the cannon as it m

oves. After it is fired, what happens to the ball? Does it fall back to the incline behind the cart, right into the cart or in front of the incline? Explain your reasoning conceptually.
Physics
1 answer:
Elena L [17]3 years ago
5 0

Answer:

Explanation:

This problem can be solved with the conservation of the momentum.

If the ball is fired upward, the momentum before and after the ball is fired must conserve. Hence, the speed of the ball is the same that the speed of the car just in the moment in wich the ball is fired.

Hence, the result depends of the acceleration of the car. If the change in the speed is higher than the speed of the ball, it is probably that the ball will be behind the car or it will come back to the car.

If the ball is fired forward, and if the change in the speed of the car is not enogh, the ball will be in front of the car.

HOPE THIS HELPS!!

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A baseball is hit so that it travels straight upward after being struck by the bat. A fan observes that it takes 3.00 s for the
Vladimir [108]

Answer:

Initial velocity = 29.43m/s b) Height it reaches = 44.145 m

Explanation:

Using the first equation of motion we have

v=u+at

here

v is the final velocity

u is the initial velocity

a is the acceleration of the object

t is time

When the ball reaches it's highest point it's velocity will become 0 as it will travel no further

Also the acceleration in our case is acceleration due to gravity (-9.8m/s^{2}) as the ball moves in it's influence alone with '-' indicating downward direction

Thus applying the values we get

0=u-(9.81)m/s^{2}\times 3\\\\u=19.43m/s

b)

By 3rd equation of motion we have

v^{2}-u^{2}=2gs

here s is the distance covered

Applying the value of u that we calculated we get

s=\frac{-u^{2}}{2g}\\\\s=\frac{-29.43^{2}}{-2\times 9.81}\\\\s=44.145m

7 0
3 years ago
what is the gravitational field strength of mars measured at a position 400 km above its surface? mars has a mass of 6.39x10^23
saul85 [17]

Answer:

G=GM/r^2

G=(6.67×10^-11)(6.39×10^23)/(3390000+400000)^2

G=(6.67×10^-11)(6.39×10^23)/(3790000)^2

G=2.967 m/s^2

Explanation:

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