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3 years ago

In Java:

Computers and Technology

1 answer:

Aleksandr-060686 [28]3 years ago

3 0

Answer:

A subclass?

Explanation:

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Bonjour ma question est: expliquer comment fonctionne une calculatrice qui ne contient pas une pile. Pouvez-vous m'aider?

larisa [96]

Answer:

Tout calculateur électronique ou numérique nécessite une source d'alimentation pour fonctionner, avec son circuit configuré à la porte logique requise liée aux touches d'entrée et à l'écran de sortie.

Explanation:

Les calculatrices sont des appareils utilisés pour les calculs arithmétiques. Au 19ème siècle, les calculatrices étaient mécaniques et n'utilisaient pas de batterie, elles étaient encombrantes et utilisaient des tiges et des engrenages dans leur fonctionnement. Les calculatrices récentes sont électroniques, alimentées par une batterie. Ils comprennent un circuit électronique configuré à sa porte logique requise pour le calcul, un bouton pour l'entrée et un écran pour la sortie du calcul.

6 0

3 years ago

It takes 2 seconds to read or write one block from/to disk and it also takes 1 second of CPU time to merge one block of records.

Alexxx [7]

Answer:

Part a: For optimal 4-way merging, initiate with one dummy run of size 0 and merge this with the 3 smallest runs. Than merge the result to the remaining 3 runs to get a merged run of length 6000 records.

Part b: The optimal 4-way merging takes about 249 seconds.

Explanation:

The complete question is missing while searching for the question online, a similar question is found which is solved as below:

Part a

For optimal 4-way merging, we need one dummy run with size 0.

Merge 4 runs with size 0, 500, 800, and 1000 to produce a run with a run length of 2300. The new run length is calculated as follows $L_{mrg}=L_0+L_1+L_2+L_3=0+500+800+1000=2300$
Merge the run as made in step 1 with the remaining 3 runs bearing length 1000, 1200, 1500. The merged run length is 6000 and is calculated as follows

$L_{merged}=L_{mrg}+L_4+L_5+L_6=2300+1000+1200+1500=6000$

The resulting run has length 6000 records.

Part b

For step 1

Input Output Time

Input Output Time is given as

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}$

Here

L_run is 2300 for step 01
Size_block is 100 as given
Time_{I/O per block} is 2 sec

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}\\T_{I.O}=\frac{2300}{100} \times 2 sec\\T_{I.O}=46 sec$

So the input/output time is 46 seconds for step 01.

CPU Time

CPU Time is given as

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}$

Here

L_run is 2300 for step 01
Size_block is 100 as given
Time_{CPU per block} is 1 sec

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}\\T_{CPU}=\frac{2300}{100} \times 1 sec\\T_{CPU}=23 sec$

So the CPU time is 23 seconds for step 01.

Total time in step 01

$T_{step-01}=T_{I.O}+T_{CPU}\\T_{step-01}=46+23\\T_{step-01}=69 sec\\$

Total time in step 01 is 69 seconds.

For step 2

Input Output Time

Input Output Time is given as

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}$

Here

L_run is 6000 for step 02
Size_block is 100 as given
Time_{I/O per block} is 2 sec

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}\\T_{I.O}=\frac{6000}{100} \times 2 sec\\T_{I.O}=120 sec$

So the input/output time is 120 seconds for step 02.

CPU Time

CPU Time is given as

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}$

Here

L_run is 6000 for step 02
Size_block is 100 as given
Time_{CPU per block} is 1 sec

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}\\T_{CPU}=\frac{6000}{100} \times 1 sec\\T_{CPU}=60 sec$

So the CPU time is 60 seconds for step 02.

Total time in step 02

$T_{step-02}=T_{I.O}+T_{CPU}\\T_{step-02}=120+60\\T_{step-02}=180 sec\\$

Total time in step 02 is 180 seconds

Merging Time (Total)

Now the total time for merging is given as

$T_{merge}=T_{step-01}+T_{step-02}\\T_{merge}=69+180\\T_{merge}=249 sec\\$

Total time in merging is 249 seconds seconds

5 0

3 years ago

What command is used to generate an RSA key pair?

Leokris [45]

Answer:

D) crypto key generate rsa

Explanation:

In cryptography, the RSA refers to Rivest–Shamir–Adleman. This is an algorithm used for encrypting and decrypting messages in computers thereby ensuring secured transmission of data. In order to generate an RSA key pair, you will use the command crypto key generate rsa while in the global configuration mode. This command has the following syntax:

crypto key generate rsa [general-keys| usage-keys| signature| encryption] [labelkey-label] [exportable] [modulus modulus-size] [storage name of device:][redundancy][on name of device:],

with each parameter having its description

5 0

3 years ago

Which of the following is not a true statement? You can import a table or a query directly from an Access database into an Excel

Lilit [14]

Answer:

does anybody know this answer?

Explanation:

no nobody does

5 0

3 years ago

A qualifier distinguishes the set of objects at the far end of the association based on the qualifier value.

Andrei [34K]

Answer:

True

Explanation: A qualifier is a term used in IT(information technology) and computer software. It is used to differentiate/ identify and select different sets of objects that are located at the far ends of a qualifier association.

A qualifier is usually used to identify an object from a set of closely related and similar objects, they are usually small boxes possibly with a rectangular shape.

7 0

3 years ago