8 - (-d) = 43
8 + d = 43 <==
Answer:
3a, 13cm 5, 1:200
Step-by-step explanation:
In the question 3 you just have to divide all of those numbers with that 5000, maybe also make them cm so it makes more sense. So 650m = 65000cm:5000= 13cm
then for the question 5, make the km to cm, so 4.2km would be 420000cm. Then you have to divide that 420000cm with the 21 cm, so 420000:21= 200. Then the scale should be 1:200
I had difficulties with these as well. If you need extra help with the task 3 please pm me :)
Answer:
Step-by-step explanation:
Tye length of the ramp can be gotten using Pythagoras theorem.
Horizontal distance = 10ft.
Vertical distance = 3ft
Length of the ramp² = 10²+3²
Length of the ramp² = 100+9
Length of the ramp² = 109
L² = 109
L =√109
L = 10.44ft
Hence the length of the ramp is 10.4ft to the nearest tenth
Answer:
d. 15
Step-by-step explanation:
Putting the values in the shift 2 function
X1 + X2 ≥ 15
where x1= 13, and x2=2
13+12≥ 15
15≥ 15
At least 15 workers must be assigned to the shift 2.
The LP model questions require that the constraints are satisfied.
The constraint for the shift 2 is that the number of workers must be equal or greater than 15
This can be solved using other constraint functions e.g
Putting X4= 0 in
X1 + X4 ≥ 12
gives
X1 ≥ 12
Now Putting the value X1 ≥ 12 in shift 2 constraint
X1 + X2 ≥ 15
12+ 2≥ 15
14 ≥ 15
this does not satisfy the condition so this is wrong.
Now from
X2 + X3 ≥ 16
Putting X3= 14
X2 + 14 ≥ 16
gives
X2 ≥ 2
Putting these in the shift 2
X1 + X2 ≥ 15
13+2 ≥ 15
15 ≥ 15
Which gives the same result as above.
9514 1404 393
Answer:
3 1/8 inches
Step-by-step explanation:
For focus-vertex distance p, the equation of the parabola can be written ...
y = x^2/(4p)
Here, we have p=8. We want to find the value of y when x=10 (the radius of the dish). That is ...
y = (10^2)/(4·8) = 100/32 = 3 1/8
The dish is 3 1/8 inches deep.
