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zaharov [31]
3 years ago
5

7.2 x 12 x 0.23 = ? Round to the nearest hundredth. 

Mathematics
2 answers:
Kruka [31]3 years ago
6 0
7.2*12*0.23 = 19.872
To round to the nearest hundredth look at the '7' because it is in the hundredths column.
Now look at the number AFTER 7, it is a 2 which means you would leave it the same.
Which means your answer would be:

A. 19.87


But IF the number after 7 was, let's say 5, you would round it up so the number would become 19.88

Nat2105 [25]3 years ago
5 0
Hey You!

7.2 × 12 × 0.23 = 19.872

Your answer is A. 19.87
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A rectangle is 15m longer than it is wide. Its perimeter is 72m. Find its length and width.
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Write an equation in slope-intercept form of the line that passes through (-1, 4) and (0,2).<br> y =
telo118 [61]

Answer:

y =( -1/2 )x + 2

Step-by-step explanation:

first step is to determine the slope of the line ( which is the rise over the run) or symbolically slope is defined as m= ∆x / ∆y, so plugging those values we get...

m= ∆x / ∆y = (-1 - 0) / (4 - 2) = -1 / 2

so next is to find the zero( y-intercept) of the function by ....

y = mx + b

y = ( -1/2)x + b (since m is equal to -1/2)

2 = ( -1/2)0 + b

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3 years ago
Evaluate 8x-y2-3 when x = -1/4 and y=3<br>plz help
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6 0
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Read 2 more answers
In the standard (x,y) coordinate plane a right triangle has vertices at (-3,4)(3,4)(3,-4) what is the length in coordinates unit
MAXImum [283]

Given:

The vertices of a right triangle are:

(-3,4),(3,4),(3,-4)

To find:

The length of the hypotenuse of the given right triangle.

Solution:

Let the vertices of the right triangle are A(-3,4),B(3,4),C(3,-4).

The distance formula is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

AB=\sqrt{(3-(-3))^2+(4-4)^2}

AB=\sqrt{(3+3)^2+(0)^2}

AB=\sqrt{(6)^2+0}

AB=\sqrt{36}

AB=6

Similarly,

BC=\sqrt{(3-3)^2+(-4-4)^2}

BC=\sqrt{(0)^2+(-8)^2}

BC=\sqrt{64}

BC=8

And,

AC=\sqrt{(3-(-3))^2+(-4-4)^2}

AC=\sqrt{(6)^2+(-8)^2}

AC=\sqrt{36+64}

AC=\sqrt{100}

AC=10

Now, taking sum of squares of two smaller sides, we get

AB^2+BC^2=6^2+8^2

AB^2+BC^2=36+64

AB^2+BC^2=100

AB^2+BC^2=AC^2

By the definition of the Pythagoras theorem, AC is the hypotenuse of the given triangle.

Therefore, the length of the hypotenuse is 10 units.

6 0
3 years ago
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