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Romashka-Z-Leto [24]
3 years ago
13

What is the inverse of the function shown?

Mathematics
1 answer:
Elena L [17]3 years ago
5 0

Answer:

¿?!¡°•○●□■♤♡◇♧☆▪︎¤₩¥£€

Bug
3 years ago
SO whats the answer?
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Marks doctors appointment was 35 minutes after Tysons appointment. Tysons appt was 20 minutes after Timothy's appt. Timothy arri
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So 9:30 17 min goes by so its 9:47 but tim arrived 8 mins before so it was 9:39 when he arrived. Next tyson arrived 20 min after tims ORIGINAL oppt 9:47 20 min 10:07 then for marks 35 min after witch is 10:12
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3 years ago
Sabina had Rs. 50,000. She deposited some amount of it in Sanima Bank
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Thanks for points broski
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3 years ago
Since an instant replay system for tennis was introduced at a major​ tournament, men challenged 1436 referee​ calls, with the re
Artemon [7]

There is no sufficient evidence to suggest that men and women have equal success in challenging calls. This was illustrated in the hypothesis.

<h3>How to compute the value?</h3>

It should be noted that based on the information given, P1 will be:

= 424/1436

= 0.295

P2 will be:

= 222/754

= 0.294

The value of the test statistic will be:

= (424 + 222)/(1436 + 754)

= 646/2190

= 0.2949

In this case, the value of the test statistic falls on the rejection region, therefore, there is no sufficient evidence to suggest that men and women have equal success in challenging calls.

Learn more about hypothesis on:

brainly.com/question/11555274

#SPJ1

4 0
2 years ago
Mason works h hours each day during the 5 day workweek. He also works 5 hours on the weekends. Write two equivalent expressions
kobusy [5.1K]

Answer:

5h+5

5(h+1)

Step-by-step explanation:

Equivalent expressions are the ones that look different but are the same. As the statement says that mason works h number of hours during the 5 day week and 5 hours on the weekend, you can write the following expression:

5h+5

h= number of hours Mason works

Then, you can find the common factor to get an equivalent expression:

5(h+1)

According to this, the equivalent expressions are:

5h+5

5(h+1)

4 0
4 years ago
Read 2 more answers
Cot^4θ-4cot^2θ-5=0 <br>solve for θ
stich3 [128]
\cot^4\theta-4\cot^2\theta-5=(\cot^2\theta-5)(\cot^2\theta+1)=0

\cot^2\theta-5=0\implies\cot^2\theta=5\implies\cot\theta=\pm\sqrt5

Recall that \cot\theta=\cot(\theta+\pi), which is to say \cot x has period \pi. This in turn means that \cot\theta=0 will have the same solutions as \cot(\theta+n\pi)=0 for any integer n. So the general solution to the first case is

\cot\theta=\pm\sqrt5\implies\theta=\cot^{-1}(\pm\sqrt5)+n\pi

where n is any integer.

On the other hand,

\cot^2\theta+1=0\implies\cot^2\theta=-1

but x^2\ge0 for any value of x, so this equation has no (real) solutions for \theta.
4 0
3 years ago
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