Answer:
523.3 cubic inches
Step-by-step explanation:
A basketball has a diameter of 10 in. Using = 3.14, what is the approximate volume of the basketball in cubic inches?
The shape of a basketball is spherical.
Hence:
The volume of a basketball = 4/3 × π × r³
From the question,
π = 3.14
r = radius = Diameter/2
r = 10 in/2 = 5 in
Hence:
The volume of the basketball
= 4/3 × 3.14 × 5³
= 1570 ÷ 3
= 523.33333333 cubic inches
Therefore, the approximate volume of the basketball = 523.3 cubic inches
|
|__x_- 4___________ 2x³/2x² =x
2x² + 2x +3 | 2x³ - 6x² +7x +3
- (<span>2x³ +2x² +3x)
</span> -8x² +4x +3 -8x²/2x² = -4
<span>-(-8x² -8x -12)
</span> 12x +15
(x-4) + (12x +15)/(2x² + 2x +3)
Answer:
2 7/24
Step-by-step explanation:
1 5/8 + 2/3
1 15/24 + 16/24
1 31/24 = 2 7/24
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-Chetan K
Answer:
Coordinate Q is (0.8, 0.7)
Step-by-step explanation:
We are told that the coordinates of point Pare (0.6,0.1).
This means that along the x-axis, x = 0.6 and along the y-axis, y = 0.1.
Now, by inspection of the graph, we can see that when we count boxes from the origin to the point P, we have 6 boxes. Thus, each box corresponds to 0.1. So, for point Q, from the origin to that point, on the x-axis, we have 8 boxes. Since one box = 0.1, then the x - value of Coordinate Q is 0.8.
On the y - axis, we see that we have one box from the origin up for the corresponding y-value of coordinate P.
This means that one box is 0.1.
For coordinate Q, we will count 7 boxes. Thus, y-value of coordinate Q is 0.7.
Thus,coordinate Q is (0.8, 0.7)
5x^2+4x-2 This is a second degree polynomial since the largest exponent is x^2
