The easiest way to solve this is to divide the shape into 2 rectangles.
The first rectangle being the big one on the left with the 12 and 6
and the second one being the little one on the right, next to it with the 5
So 12 x 6 = 72 (dont pay attention to the 7, 5, or 10, because all we need is 1 length and 1 width)
And for the smaller one it is a little bit trickier.
So on the bottom we see that is says 10ft, but we cant use that because what we really need is the measurement between the 5 and 7 on the top of the little rectangle
At the top we see that it says 6ft
We can do 10-6 to find the missing measurement.
Because the length of the whole like is 10, and the length of one of the little lines is 6, so the length of 6 + some number =10
So 10-6 = 4
Which means the number we need is 4
So now we have 5 x 4 = 20
72 + 20 = 92
Answer: 92
I also attatched an image, I hope this helps! Ask me if you have any other questions about this problem!
#1) 4.445 ft
#2) yes
Explanation
#1) The maximum height is the y-coordinate of the vertex. We first find the axis of symmetry, given by x=-b/2a:
x=-0.17/2(-0.005) = -0.17/-0.01 = 17
Plugging this into the equation,
y=-0.005(17²)+0.17(17)+3 = 4.445
#2) Substituting 30 into the equation,
y=-0.005(30²) + 0.17(30) + 3 = 3.6
The ball will 3.6 in the air, so yes, it will clear the 3 ft tall net.
F^-1(x)= x/9 + 1/3
To find this, just interchange the variables and solve for y.
y=9x-3
x=9y-3
x+3=9y
divide by nine
Answer:
0.6
Step-by-step explanation:
We can get the answer by subtracting the decimal by one.
2/5 = 0.4
1 - 0.4 = 0.6