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aksik [14]
3 years ago
6

What is the answer to the q

Mathematics
1 answer:
satela [25.4K]3 years ago
5 0

Answer:

starting from (0,0),go to the 6 units and up 1

Step-by-step explanation:

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Write 15+45 as a product of two factors using the gcf and the distributive property
valkas [14]

Answer:

15(1 + 3)

Step-by-step explanation:

15 written in its prime factors is 3 × 5 (15 × 1)

45 written in its prime factors 3 × 3 × 5 (15 × 3)

The greatest common factor is 15: 15 × 1 = 15 and 15 × 3 is 45

∴ 15 + 45 = 15(1 + 3)

Hope this helps! Make me brainiest, lol it's fine if you don't. : )

5 0
2 years ago
I'll give points just please help(it's a little long sorry:( A student randomly selects some crayons from a large bag of crayons
andrey2020 [161]

the probability of selecting a blue crayon for the bag is 16.7% while estimate probability of selecting a red crayon is 20% and the most likely crayon to be selected is brown crayon and also the possibility of getting a real possibility of the number of crayons in the bag is 60

3 0
3 years ago
What is the value of x?
Trava [24]

The sum of a polygon's angles are 540.

When you add all the angles together here, you get 456.

Now subtract 456 from 540.

540 - 456 = 84

7 0
3 years ago
For which pairs of functions is f(g(x))=x?
Nastasia [14]
The answer is B. 
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5 0
3 years ago
Read 2 more answers
A study showed that 69% of supermarket shoppers believe supermarket brands to be as good as national name brands. To investigate
Valentin [98]

Answer:

We conclude that supermarket ketchup was not as good as the national brand ketchup.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 100

p = 69% = 0.69

Alpha, α = 0.05

Number of stating that the supermarket brand was as good as the national brand , x = 56

a) First, we design the null and the alternate hypothesis

H_{0}: p = 0.69\\H_A: p \neq 0.69

This is a two-tailed test.  

b) Formula:

\hat{p} = \dfrac{x}{n} = \dfrac{56}{100} = 0.56

z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

Putting the values, we get,

z = \displaystyle\frac{0.56-0.69}{\sqrt{\frac{0.69(1-0.69)}{100}}} = -2.810

Now, we calculate the p-value from the table.

P-value =  0.0049

c) Since the p-value is lower than the significance level, we fail to accept the null and reject it.

Thus, we conclude that supermarket ketchup was not as good as the national brand ketchup.

d) It need to be tested further whether the supermarket brand was worse than the national brand or better than the national brand.

6 0
3 years ago
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