Answer:
#include<iostream>//library inclusion
using namespace std;
int main()
{
int userInput;
do//start of do while loop
{
cout << "Enter a number less than a 100" << endl;
cin >> userInput;
if (userInput < 100) //condition
{
cout << "YOu entered less than a hundred: " << userInput << endl;
}
else
{
cout << "your number is greater than 100" << endl;
}
} while (userInput > 100);//condition for do while
return 0;//termination of int main
}
Explanation:
The program has been commented for you. The do-while loop enters the first loop regardless of the condition. Then after the first iteration, it checks for the condition. If the condition is being met, it will iterate through, again. Otherwise it will break out of the loop and land on the "return 0;" line. Which also happens to be the termination of the program in this case. The if-else condition is used for the user to see when prompted.
Answer:
Explanation:
In this exercise, you will roll a pair of dice until the numbers add up to a given number. You can assume that the given number is 2, 3, 6, or 12. Using pseudocode, write an algorithm that returns the number of times the dice is rolled to achieve this number.
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brainly.com/question/28860592
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Answer:
In Python:
def gcd(m,n):
if n == 0:
return m
elif m == 0:
return n
else:
return gcd(n,m%n)
Explanation:
This defines the function
def gcd(m,n):
If n is 0, return m
<em> if n == 0:
</em>
<em> return m
</em>
If m is 0, return n
<em> elif m == 0:
</em>
<em> return n
</em>
If otherwise, calculate the gcd recursively
<em> else:
</em>
<em> return gcd(n,m%n)</em>
<em />
<em>To call the function to calculate the gcd of say 15 and 5 from main, use:</em>
<em>gcd(15,5)</em>
