How do i find the slant asymptope of x^3/(2(x+2)(x-4) aka x^3/(2x^2-8)
1 answer:
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Answer: y-intercept: (0, 12)
Step-by-step explanation:
= 9 − 3 (n − 1)
Use the slope-intercept form to find the slope and y-intercept.
The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
y = mx + b
Find the values of m and b using the form y = mx + b.
m = −3
b = 12
The slope of the line is the value of m, and the y-intercept is the value of b.
Slope: −3
intercept: (0, 12)
Any line can be graphed using two points. Select two x values, and plug them into the equation to find the corresponding y values.
Find the x-intercept.
To find the x-intercept(s), substitute in 0 for y and solve for x.
0 = −3x + 12
Solve the equation.
Rewrite the equation as −3x + 12 = 0.
−3x + 12 = 0
Subtract 12 from both sides of the equation.
−3x = −12
Divide each term by −3 and simplify.
x = 4
x-intercept(s) in point form.
x-intercept(s): (4, 0)
Find the y-intercept.
To find the y-intercept(s), substitute in 0 for x and solve for y.
y = −3 ⋅ 0 + 12
Solve the equation.
Remove parentheses.
y = −3 ⋅ 0 + 12
Simplify −3 ⋅ 0 + 12.
y = 12
intercept(s) in point form.
intercept(s): (0, 12)
Create a table of the x and y values.
<u> x | y </u>
0 | 12
4 | 0
Graph the line using the slope and the y-intercept, or the points.
Slope: −3
intercept: (0, 12)
