Answer:
The correct option is B
i just answer that on our test and i got A+
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we know that
The measure of the external angle is the semidifference of the arcs that it covers
so
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
Let
x------> minor arc MN
major arc MN=360-x
substitute in the formula above
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x
x=104.14°
therefore
the answer is
the measure of arc MN (minor arc) is 104.14°
Answer:
(- 1, 1) and (- 5, - 35)
Step-by-step explanation:
since both equations express y in terms of x, equate the right sides
x² + 15x + 15 = - x² + 3x + 5 ( subtract - x² + 3x + 5 from both sides )
2x² + 12x + 10 = 0 ( divide all terms by 2 )
x² + 6x + 5 = 0 ← in standard form
(x + 1)(x + 5) = 0 ← in factored form
equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
x + 5 = 0 ⇒ x = - 5
substitute these values into either of the 2 equations and solve for y
x = - 1 : y = (- 1)² + 15(- 1) + 15 = 1 - 15 + 15 = 1 ⇒ (- 1, 1 )
x = - 5 : y = (- 5)² + 15(- 5) + 15 = 25 - 75 + 15 = - 35 ⇒ (- 5, - 35 )
None of the given options
Answer:
1 1/8
Step-by-step explanation:
3/8+ 3/8= 6/8+3/8=1 1/8