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eimsori [14]
3 years ago
6

5 tens + 6 ones = 4 tens + ___ ones

Mathematics
1 answer:
charle [14.2K]3 years ago
5 0

Answer:

16 ones

Step-by-step explanation:

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Answer:

I gotchu homie:

1. Slope = 5

2. Slope = 2/3

3. Slope = 3/4

4. Slope = 5/2

If you want to understand how to find them feel free to ask :)

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What percent of 55 is 21.1
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11.6, if you need a decimal. it's in between 11 and 12

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You work at Dave's Donut Shop. Dave has asked you to determine how much each box of a dozen donuts should cost. There are 12 don
slava [35]
A box of donuts would cost: b = 3.84 + 0.18f

First, we have to find the total cost of the donuts. 
12 x 0.32 = 3.84

Next, we need to determine the cost of the box. However, we don't know the surface area, just the cost per foot. We can multiply the number of square feet of the box by $0.18 to find the cost.

So our equation could be:  b = 3.84 + 0.18f (where f is the surface area of the box in square feet)
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What is the quotient?<br><br> <img src="https://tex.z-dn.net/?f=X-3%5Csqrt%7Bx%7D%204X%5E2%2B3X%2B2" id="TexFormula1" title="X-3
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Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.
suter [353]

Answer:

\theta = 30^\circ, 330^\circ

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

Step-by-step explanation:

Given [Missing from the question]

Equation:

cos\theta = \frac{\sqrt 3}{2}

Interval:

0 \le \theta \le 360

0 \le \theta \le 2\pi

Required

Determine the values of \theta

The given expression:

cos\theta = \frac{\sqrt 3}{2}

... shows that the value of \theta is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

cos\theta = \frac{\sqrt 3}{2}

Take arccos of both sides

\theta = cos^{-1}(\frac{\sqrt 3}{2})

\theta = 30 --- In the first quadrant

In the fourth quadrant, the value is:

\theta = 360 -30

\theta = 330

So, the values of \theta in degrees are:

\theta = 30^\circ, 330^\circ

Convert to radians (Multiply both angles by \pi/180)

So, we have:

\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}

\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}

\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

8 0
2 years ago
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