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julsineya [31]
3 years ago
6

Which equation below shows the relationship for the graph

Mathematics
1 answer:
mezya [45]3 years ago
7 0

Answer:

there arent any equations listed

Step-by-step explanation:

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A light bulb consumes 960 watt-hours per day. How many watt-hours does it consume in 3 days and 18 hours?
oksano4ka [1.4K]

960 x 3 = 2880

18/24 = 0.75

960x 0.75 = 720

2880 + 720 = 3600

7 0
3 years ago
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To determine the order that cars line up for the Daytona 500, drivers must complete qualifying laps around the Daytona Internati
sergey [27]

Answer:

The frequency of the car is 0.0233743 laps/sec and 1.4024 laps were completed in 60 seconds

5 0
3 years ago
What is the maximum Number of different sizes of faces that a rectangular Prism can have.
telo118 [61]

Answer:

3

Step-by-step explanation:

For a rectangular prism of dimensions L × W × H, pairs of opposite faces will have dimensions ...

  • L × W
  • W × H
  • H × L

These will be three different sets of dimensions if L, W, and H are all different lengths.

7 0
3 years ago
21=3(y+3) which value of y is the solution to the equation?
Neporo4naja [7]
Y=4 pls brainliest me thanks
7 0
3 years ago
Read 2 more answers
How do I do 8b(ii) ? Please help me thank you!
Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


7 0
3 years ago
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