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Vinil7 [7]
3 years ago
5

What is the sum? 4+ (-9) + (-4) =

Mathematics
1 answer:
Gnoma [55]3 years ago
8 0

Answer:

-9

Step-by-step explanation:

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Lilit [14]

Answer:

The answer to this question is D.60



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4 years ago
Can someone help on number 32 please
STatiana [176]

Answer:

b. -2.5, -\frac{5}{4}, -\frac{2}{3}, 0.75, \sqrt{3}, 1.9,  I-4I

Step-by-step explanation:

-5/4 is smaller than -2/3 since on the negative sides, any number who is larger is smaller.

0.75 is smaller than the square root of 3 since that equals to 1.7.

1.9 is smaller than the absolute value of -4 since that equals to 4.

4 0
3 years ago
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What % of 80 is 40 <br> show work please
Damm [24]

Answer:

50%

Step-by-step explanation:

40/80 = 0.5.  We multiply this decimal fraction by 100% to obtain the desired percentage:  0.5(100%) = 50%

8 0
3 years ago
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Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125
Savatey [412]

we have that

300 + 150 + 75 +...

Let

a1=300\\ a2=150\\ a3=75

we know that

\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50

\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50

so

a(n+1)=an*0.50

Is a geometric sequence

Find the value of a4

a(4)=a3*0.50

a(4)=75*0.50

a(4)=37.5

Find the value of a5

a(5)=a4*0.50

a(5)=37.5*0.50

a(5)=18.75

Find S5

S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25

therefore

the answer is

581.25

Alternative Method

Applying the formula

S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25

therefore

the answer is

581.25

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3 years ago
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At 5:00pm the temperature read 10° above zero. At midnight it read 4 ° below zero. Find the change
larisa86 [58]
The temperature changed a total of 14° over the course of 7 hours with an average change of 2° per hour drop.
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