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3 years ago

6

Please help asap!!!!!!

1 answer:

Veseljchak [2.6K]3 years ago

7 0

Answer:

one point will be on (3,2) another on (5,3) and 1 more on (6,6)

Step-by-step explanation: not sure if this is 100% correct or not

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Mike has 18 goldfish 24 silverfish in his Aquarium what is the ratio of silverfish to Total fish in the aquarium

pav-90 [236]

Answer:

24:42 or 4:7

Step-by-step explanation:

Silverfish : Total fish

24 : 24 + 18

24 : 42

Simplify:

24:42 = 4:7

7 0

3 years ago

A rectangular storage container with an open top is to have a volume of 10 m3 . then length of its base is twice the width. mate

katrin [286]

Answer:

The cost of materials for the cheapest such container is $163.54.

Step-by-step explanation:

A rectangular storage container with an open top is to have a volume of 10 m³.

The volume of the rectangle is

$\text{Volume} =\text{Length} \times \text{Width} \times \text{Height}$

Length of its base is twice the width.

Let Width be 'w'.

Length is l=2w.

Height be 'h'.

$10 =2w\times w\times h$

$10=2w^2h$

The height in terms of width is represented as,

$h=\frac{10}{2w^2}$

$h=\frac{5}{w^2}$

According to question,

The cost is 10 times the area of the base and 6 times the total area of the sides.

i.e. Cost is given by,

$C=10(L\times W)+6(2\times L\times H+2\times W\times H)$

$C=10(2w\times w)+6(2\times 2w\times \frac{5}{w^2}+2\times w\times \frac{5}{w^2})$

$C=20w^2+\frac{120}{w}+\frac{60}{w}$

$C(w)=20w^2+\frac{180}{w}$

To get the minimum value,

Differentiate the cost w.r.t 'w',

$C'(w)=20\frac{d(w^2)}{dw}+180\frac{d(w^{-1})}{dw}$

$C'(w)=20\times 2w-180 w^{-2}$

$C'(w)=40w-\frac{180}{w^2}$

To find critical points put derivate =0,

$40w-\frac{180}{w^2}=0$

$40w=\frac{180}{w^2}$

$w^3=\frac{180}{40}$

$w=\sqrt[3]{4.5}$

$w=1.65$

We find the second derivative to minimize,

$C''(w)=40\frac{d(w)}{dw}-180\frac{d(w^{-2})}{dw}$

$C''(w)=40+360(w^{-3})$

$C''(w)>0$

As $C''(w)>0$ it is the minimum cost.

The cost is minimum at w=1.65.

Substitute the values in the cost function,

$C(1.65)=20(1.65)^2+\frac{180}{1.65}$

$C(1.65)=54.45+109.09$

$C(1.65)=163.54$

Therefore, the cost of materials for the cheapest such container is $163.54.

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4 years ago

For which operations is the Commutative Property true?

sladkih [1.3K]

Addition and multiplication

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3 years ago

Sally had 5 dollars she gave Kim 3 how much do she has

Ainat [17]

2 dollars remaining........

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3 years ago

Read 2 more answers

The regular price of a pair of jeans is $40. This week, the jeans are on sale, and Jim saved $14. What percent of the original p

nordsb [41]

well, if we take 40 to be the 100%, what is 14 off of it in percentage?

$\begin{array}{ccll} amount&\%\\ \cline{1-2} 40 & 100\\ 14& x \end{array} \implies \cfrac{40}{14}~~=~~\cfrac{100}{x}\implies \cfrac{20}{7}=\cfrac{100}{x} \\\\\\ 20x=700\implies x=\cfrac{700}{20}\implies x=35$

5 0

2 years ago