Question

Two thirds of a number decreased by 27 is at least 9

Answer 1

Answer:

The mathematical statement can be written as follows

$\frac{2}{3}x-27\geq9$

which has solution as

⇒  $x\geq54$

Step-by-step explanation:

Given:

Two thirds of a number decreased by 27 is at least 9.

This statement can be transformed into a mathematical statement.

Taking the unknown number as $x$ and putting the inequality $\geq9$ as the result is at least 9.

So, we have

$\frac{2}{3}x-27\geq9$

Adding 27 both sides

$\frac{2}{3}x-27+27\geq 9+27$

$\frac{2}{3}x\geq 36$

Multiplying both sides by 3.

$3\times\frac{2}{3}x\geq 36\times 3$

$2x\geq108$

Dividing both sides by 2.

$\frac{2x}{2}\geq\frac{108}{2}$

∴ $x\geq54$