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IrinaVladis [17]
3 years ago
14

...............2+2-2+2+2-4+2

Mathematics
2 answers:
kirill115 [55]3 years ago
8 0

<em>Hi</em><em> </em><em>your</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>4</em><em>.</em><em>.</em>

<em>Please</em><em> </em><em>follow</em><em> </em><em>me</em><em>.</em><em>.</em>

alexgriva [62]3 years ago
5 0

Answer:

4

Step-by-step explanation:

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iogann1982 [59]

Answer: what is the question

Step-by-step explanation:

8 0
3 years ago
While grading her students' most recent quiz on equation solving, Mrs. Jones calculated that approximately forty percent of her
EastWind [94]

The given equation is,

3(-n+4)+5n=2n

Part 1:

Solve the above equation for n.

Using distributive property of multiplication,

\begin{gathered} -3n+3\times4+5n=2n \\ -3n+12+5n=2n \end{gathered}

Now, group the like terms.

-3n+5n-2n+12=0

Now, add the like terms.

\begin{gathered} -5n+5n+12=0 \\ 0=-12 \end{gathered}

0=-12 is a false statement.

Since we obtained a false statement, the given equation has no solution.

So, option b is correct.

Part 2:

The option (a) is n=3.

If while solving an equation, a single value is obtained for the variable, then the equation has only a single solution. If n=3 is obtained after solving the equation, then the student should chose option (a) as the answer.

The option (b) is "no solution".

While solving an equation, if we obtain an equation which is mathematically false, then the equation will have no solution. So, no solution is chosen when no value is obtained for n and the final equation is mathematically false.

The option (c) is "infinitely many solutions".

While solving an equation, if we obtain an equation which is mathematically correct such as 0=0, 7=7 etc., then the equation will have infinietly many solutions. So, infinitely many solutions is chosen when no value is obtained for n and the final equation is mathematically correct.

8 0
1 year ago
find a two variable identity by incorporating a second variable y into the single variable identity note that x&gt;1,x&gt;y, and
Talja [164]

we in the same boat we should work together

7 0
3 years ago
Read 2 more answers
Find the nonpermissable replacement for the variable in this expression 3x over 5x+2
kotegsom [21]
5x + 2 is a denominator.
A denominator cannot equal zero since division by zero is undefined.
Set the denominator equal to zero and solve for x to find which value of x makes the denominator zero.

5x + 2 = 0

5x = -2

x = -2/5

The non-permissible replacement for the variable is -2/5.
5 0
4 years ago
The midpoint of JK is M(4, 5). One endpoint is J(5,2). Find the coordinates of the other endpoint K.
Bogdan [553]

Answer:

9

Step-by-step explanation:

not 9

7 0
3 years ago
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