Yo sup??
the answer is 1 because
P(E)+P(E')=1
where E is the event and
E' is the complement of the event
Hope this helps
The answer to this question would be: <span>The new survey’s margin of error will be between 50% and 100% the size of the original survey’s margin of error.
A bigger sample will result in a narrower margin of error which is a good thing because your data will become more accurate. But twice size will not improve the margin into the half. It definitely became lower than 100% though
</span>
Answer:
Correct me if Im wrong but I think that it is 3 to the -5th power
Step-by-step explanation:
Answer:
about 4312
Step-by-step explanation:
You want the total cost for n CDs to be 3.50n.
The manufacturer will charge you 9700+1.25n, so you want these to be equal:
3.50n = 9700 +1.25n
2.25n = 9700 . . . . . . . . subtract 1.25n
n = 9700/2.25 ≈ 4311.111...
Producing 4312 CDs will make the cost per CD slightly less than $3.50.
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Producing 4311 CDs will make the cost per CD be about $3.500058. Producing 4312 CDs will bring it down to $3.499536.
