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velikii [3]
2 years ago
15

To convert from Celsius (©) to Fahrenheit (F), the formula 3C + 32 = Pis uued. It is currently 22

Mathematics
1 answer:
andrew-mc [135]2 years ago
7 0

Answer:

71.6 °F

Step-by-step explanation:

The formula to find a Celsius temperature from Fahrenheit is: °F = (°C × 9/5) + 32. Insert 22 for °C and solve.

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I need help with my math can you help me ​
MrRissso [65]

Answer:

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3 0
3 years ago
The area of a circle is 201 cm². What is the diameter
natima [27]

Answer:

The diameter would be 16

Step-by-step explanation:

The area of a circle is a=r^{2}×π. Now just plug in the values you have which is you area. 201=r^{2}×π now divide by pi on both sides you that you get about 64=r^{2}. Now find the square root on both sides which will then give you 8 as your radius. To find diameter from radius you have to multiply by 2. 8*2=16

8 0
3 years ago
Jon, Leroy, and Simon are having a free-throw shooting contest. Each boy
Zolol [24]

Answer:

B

Step-by-step explanation:

If you arrange a statistics in order from least to greatest, the middle number is the median.

If there is even number of numbers in a list, let it be n numbers, then we take the average of n/2th and n/2 + 1 th terms.

Here, all of them have 6 numbers, so 6/2 = 3  and 4th, we take average of 3rd and 4th number to find the median.

Since they are arrange in order we check each:

Jon = average of 6 and 7, (6+7)/2 = 6.5

Leroy = average of 6 and 8,  (6+8)/2 = 7

Simon = average of 5 and 6, (5+6)/2 = 5.5

Leroy's median is the greatest (7).

8 0
3 years ago
Read 2 more answers
Navy PilotsThe US Navy requires that fighter pilots have heights between 62 inches and78 inches.(a) Find the percentage of women
Zigmanuir [339]

The first part of the question is missing and it says;

Use these parameters: Men's heights are normally distributed with mean 68.6 in. and standard deviation 2.8 in. Women's heights are normally distributed with mean 63.7 in. and standard deviation 2.9 in.

Answer:

A) Percentage of women meeting the height requirement = 72.24%

B) Percentage of men meeting the height requirement = 0.875%

C) Corresponding women's height =67.42 inches while corresponding men's height = 72.19 inches

Step-by-step explanation:

From the question,

For men;

Mean μ = 68.6 in

Standard deviation σ = 2.8 in

For women;

Mean μ = 63.7 in

Standard deviation σ = 2.9 in

Now let's calculate the standardized scores;

The formula is z = (x - μ)/σ

A) For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.7224

So, percentage of women meeting the height requirement is 72.24%.

B) For men;

Z = (62 - 68.6)/2.8 = -2.36

Z = (78 - 68.6)/2.8 = 3.36

Thus, the probability of only men will take the form of;

P(-2.36 < Z < 3.36) = P(Z<3.36) - P(Z > - 2.36)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<3.36) = 0.99961

And P(Z > -2.36) = 0.99086

Thus;

P(Z<3.36) - P(Z > -2.36) 0.99961 - 0.99086 = 0.00875

So, percentage of women meeting the height requirement is 72.24%.

B)For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.00875

So, percentage of women meeting the height requirement is 0.875%

C) Since the height requirements are changed to exclude the tallest 10% of men and the shortest10% of women.

For women;

Let's find the z-value with a right-tail of 10%. From the second table i attached ;

invNorm(0.90) = 1.2816

Thus, the corresponding women's height:: x = (1.2816 x 2.9) + 63.7= 67.42 inches

For men;

We have seen that,

invNorm(0.90) = 1.2816

Thus ;

Thus, the corresponding men's height:: x = (1.2816 x 2.8) + 68.6 = 72.19 inches

7 0
3 years ago
What is the best estimate for the following quotient 891.3/28
Lynna [10]
The answer is 31.832142857.
4 0
3 years ago
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