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4 years ago

Write the slope intercept form of the equation of each line given the slope and y intercept

Mathematics

1 answer:

drek231 [11]4 years ago

4 0

Answer:

the slope intercept form would look like this: y=6/5x+(-2)

Step-by-step explanation:

How to write slope-intercept form:

y=(slope)x+(y-intercept)

If you have the y-intercept and the slope, you can figure out this form.

Hope this helped!! :)

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Y=3x-2 what is the value of y? when y=-1/3

Olin [163]

Oddly enough, when y=-1/3, the value of y is -1/3.

When x = -1/3, the value of y is
.. y = 3*(-1/3) -2
.. = -1 -2
.. = -3

When x = -1/3, the value of y is -3.

7 0

4 years ago

Quiz

Leto [7]

Answer:

1. 50⁴ + 2³ =6250008

2. 3³ x 4²= 432

Step-by-step explanation:

I just put it into the desmos scientific calculator. If your teacher lets you, it is a good calculator.

3 0

3 years ago

4. Phil bought a block of cheese in the shape of a triangular prism measuring 8 inches by 4 inches by 2 inches. What is the volu

makkiz [27]

Answer:

32 inches^3

Step-by-step explanation:

Volume = 1/2 ( base x height x length)

0.5 ( 4 x 2 x 8) = 32 inches^3

6 0

3 years ago

"if the standard deviation of a group of 20 scores is 15, what is the variance?"

DerKrebs [107]

We have been given that the standard deviation of a group of 20 scores is 15 and we are asked to find variance.

Since we know variance is square of standard deviation. In order to find out the variance of the given data we have to take the square of 15.

$\text{ Variance}=\sigma^{2}\\
=15^{2}=225$

Therefore, our variance is 225.

7 0

3 years ago

(4x + 4)(ax – 1) – x2 +4

Oksana_A [137]

Answer:

b=-3

Step-by-step explanation:

If the expression simplifies to bx that means the $x^{2}$ terms and the constant terms must be cancel out.

Simplify it first.

$(4x+4)(ax-1)-x^{2} +4\\=(4ax^{2} -4x+4ax-4)-x^{2} +4\\=4ax^{2} -x^{2} -4x+4ax-4+4\\=4ax^{2} -x^{2} -4x+4ax$

We know –4 + 4 will cancel out. If we simplify this expression to only an x term, then the $x^{2}$ terms should be cancelled. Therefore, we say that 4ax^2 – x^2 = 0.

$4ax^{2} -x^{2} =0\\x^{2} (4a-1)=0\\4a-1=0\\4a=1\\a=\frac{1}{4}$

If we put a = ¼, then we can find the value of b:

$=4(\frac{1}{4} )x^{2} -x^{2} -4x+4(\frac{1}{4} )x\\=x^{2} -x^{2} -4x+x\\ (cancel out x^{2} terms)\\$

$=-3x$

$bx=-3x\\$ if the expression is equivalent to bx

Therefore, b = –3.

8 0

3 years ago