X ×2 + 3x -4>0
2x+3x-4>0
5x>4
x>4\5
x>0.8
I think that this right answer
I believe the answer would be B, since both situations give you 6 chances at drawing/rolling the right number/marble.
I suspect 4/2 should actually be 4/3, since 4/2 = 2, while 4/3 would make V the volume of a sphere with radius r. But I'll stick with what's given:





In Mathematica, you can check this result via
D[4/2*Pi*r^3, r]
Answer:
Are you in Connexus ?
Step-by-step explanation: