Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Answer:
Dive by n square root two, also option one.
Step-by-step explanation:
The first step to any algebra equation is to isolate the variable and you do that by divide square root 2 since it cancels out on the left side and now n is alone.
Hoped that helped :)
C) $694.25
Why?
Because you want to times the interest by 2 (1 is for one year but u want to find the amount after two years) then you multiply the amount given to each bank separately so:
400*0.07 (7% which is 7/100) = 28
250*0.065 (6.5% which is 65/1000) = 16.25
Then u add the interests together:
28+16.25 = 44.25
Finally you add that to the amount you started with:
$650+$44.25= $694.25
Answer:
1.5w = s
Step-by-step explanation:
