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3 years ago

3х+бх What is 3x +6x simplified

2 answers:

6 0

9x. Simply add the 3 and 6. You can do that because they both have the same variable. You have 3 x’s and 6 x’s, so you’ll have 9 x’s.

balu736 [363]3 years ago

3 0

Answer:

Step-by-step explanation:

because they're like terms add them together

3x + 6x = 3 + 6 =

9x, could i have brainliest if possible thanks!

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2019 Chapter Sprint Round, #20

nadezda [96]

Answer:

$Speed\ of\ car=38\ km/h$

Step-by-step explanation:

Distance Covered by Horse:

$Speed\ of\ horse=50\ km\h=50\times \frac{1000}{60}\ meter/ minute\\\\Speed\ of\ horse=\frac{2500}{3}\ meter/minute\\\\Distance\ covered\ in\ 4\ minutes=speed\times time=\frac{2500}{3}\times 4\\\\Distance\ covered\ in\ 4\ minutes=\frac{10000}{3}\ meters\\\\$

Distance covered by Car:

$Let\ speed\ of\ car=x\ meter/minute\\\\time=4\ minutes\\\\Distance\ covered=speed\times time=4\times x=4x$

$Distance\ covered\ by\ horse=Distance\ covered\ by\ car+800\\\\\frac{10000}{3}=4x+800\\\\4x=\frac{10000}{3}-800\\\\4x=\frac{7600}{3}\\\\x=\frac{7600}{3\times 4}\ meter/minute\\\\x=\frac{7600}{3\times 4}\times \frac{60}{1000}\ km/h\\\\x=38\ km/h$

7 0

3 years ago

What is the answer to 12 + 35 + 24 + 56 + 92 + 16 + 23 x 23 x 45 x 0 ?

8_murik_8 [283]

I will come back to this when I am older

7 0

3 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

3 years ago

-3n-5 , please help

Mila [183]

Answer:

(0,-5)

Step-by-step explanation:

3 0

4 years ago

Find the value of X. If necessary, round the answer to the nearest 10th. The figure is not drawn to scale.

max2010maxim [7]

Answer:

Step-by-step explanation:

You know that the length of the lines are equal, therefore the value of the angles should also be equal.

Think of it this way:

The greater the angle, the greater the line and vice versa.

Hope this helps.

6 0

3 years ago