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Ratling [72]
3 years ago
9

You are wakeboarding on a river. You travel 2 miles downstream to a marina for supplies, and then you travel 3 miles upstream to

a dock. The boat travels x miles per hour during the entire trip, and the river current is 3 miles per hour.
Mathematics
1 answer:
klemol [59]3 years ago
7 0

Answer:5x+3/(x+3)(x-3)

Step-by-step explanation:

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I need help with surface area
patriot [66]

Answer:

Surface Area varies by object/shape.

Ask your teacher/learning helper for those formulas of surface area

Step-by-step explanation:

Surface area is the sum of all faces (or surfaces) on a 3D shape. A cuboid has 6 rectangular faces. To find the surface area of a cuboid, add the areas of all 6 faces. We can also label the length (l), width (w), and height (h) of the prism and use the formula, SA=2lw+2lh+2hw, to find the surface area.

4 0
3 years ago
The 7th grade basketball team has won 15 games out of the 20 games they have played this season. If they were to keep up this wi
uranmaximum [27]

Answer: 3/4

Step-by-step explanation:

4 0
3 years ago
If sin theta = - squrt.3/2 and pi < theta < 3pi/2, what are the values of cos theta and tan theta?
Kryger [21]
So this first wants you to find where sin is √3/2 when θ is between π and 3π/2. θ would therefore be located at 2π/3.

Now plug in the value of θ for cosine:

cos (2π/3) = -1/2

And tangent:

tan (2π/3) = -√3/3
7 0
3 years ago
Read 2 more answers
All of number one thank you
Vadim26 [7]
I'm going to divide number one to 6 parts
1. \frac{4}{10} = \frac{40}{100}
2. \frac{7}{10} = \frac{70}{100}
3. \frac{2}{10} = \frac{20}{100}
4. \frac{9}{10} = \frac{90}{100}
5. \frac{18}{10} = \frac{180}{100}
6. \frac{26}{10} = \frac{260}{100}

because to make the denominator to 100, you need to multiply 10 by 10 which is 100.
and because you multiply 10, you also have to multiply the numerator by 10.
EXAMPLES: \frac{3}{10} = \frac{3}{10} × \frac{10}{10} = \frac{30}{100}
6 0
3 years ago
Read 2 more answers
Find all values of the angle θ (in radians, with 0 ≤ θ < 2π) for which the matrix a = cos θ −sin θ sin θ cos θ has real eigen
harina [27]

The matrix

A=\begin{bmatrix}\cos\theta&-\sin\theta\\\sin\theta&\cos\theta\end{bmatrix}

has eigenvalues \lambda such that

\det(A-\lambda I)=\begin{vmatrix}\cos\theta-\lambda&-\sin\theta\\\sin\theta&\cos\theta-\lambda\end{vmatrix}=0

(\cos\theta-\lambda)^2+\sin^2\theta=0

(\cos\theta-\lambda)^2=-\sin^2\theta

\cos\theta-\lambda=\pm\sqrt{-\sin^2\theta}

\lambda=\cos\theta\pm\sqrt{-\sin^2\theta}

\sin^2\theta\ge0 for all values of \theta, so we need to have \sin\theta=0 in order for \lambda to be real-valued. This happens for

\sin\theta=0\implies\theta=n\pi

where n is any integer, and over the given interval we have \theta=0 and \theta=\pi.

4 0
3 years ago
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