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sineoko [7]
3 years ago
6

A Petri dish is growing bacteria. It starts with 3 cells on day 1, 9 cells on day 2, and continues tripling the number of cells

every day after that. How many cells of bacteria are there on day 5? 3 5 5 3 15 18
Mathematics
1 answer:
n200080 [17]3 years ago
3 0

Answer:

243

Step-by-step explanation:

Given that:

Day 1 = 3

Day 2 = 9

After the 2nd day, number of cells continue to triple ;

Day 3 = 9^3

P(t) = 9 * 3^3

P(t) = 9 * 27

= 243

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Answer:

120 blocks total

Step-by-step explanation:

All of the little cubes have side length 2"  Thus, the 11" height of the box cannot be used entirely:  we waste the top 1" because the five layers of little cubes reach only to 10" from the bottom.

Start at the bottom of the box.  The dimensions of the bottom are 12" by 8".  Along the longer side we can lay 6 blocks (which add up to 12" and are 2" wide.  We can add 3 more such rows to fill the available 8" width of the box bottom.  That's 6*4, or 24 blocks.

We can add 4 more 6 block by 4 block layers before we have the maximum 5 layers stacked in the box.

5 layers times 24 blocks per layer comes to 120 blocks total.

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lidiya [134]

Answer:

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Step-by-step explanation:

M = (x_M, \; y_M)

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Answer:

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Step-by-step explanation:

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