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3 years ago

6

A Petri dish is growing bacteria. It starts with 3 cells on day 1, 9 cells on day 2, and continues tripling the number of cells

every day after that. How many cells of bacteria are there on day 5? 3 5 5 3 15 18

1 answer:

n200080 [17]3 years ago

3 0

Answer:

243

Step-by-step explanation:

Given that:

Day 1 = 3

Day 2 = 9

After the 2nd day, number of cells continue to triple ;

Day 3 = 9^3

P(t) = 9 * 3^3

P(t) = 9 * 27

= 243

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Answer:

Option C

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Step-by-step explanation:

Let

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y-----> the cost of each sandwich

we know that

$3x+2y=27$ -----> equation A

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Multiply the equation B by $-2$

$-2(2x+y)=-2*16$ -----> $-4x-2y=-32$ ------> equation C

Adds equation A and equation C

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Substitute the value of x in the equation B

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$y=6$

The solution of the system of equations is the point $(5,6)$

so

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