3 years ago

Rewrite (5y)^1/2 as a radical.

1 answer:

7 0

√(5y)^(1/2) haci es en radical

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alekssr [168]

Answer:

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Step-by-step explanation:

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NNADVOKAT [17]

Answer:

Step-by-step explanation:

10a-15b

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Marat540 [252]

81-(3x-2)^2
= 81-(-6)^2
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3 years ago

sladkih [1.3K]

Answer:

$Q'=(4,1)\\R'=(6,-5)\\S'=(3,-4)\\T'=(1,-1)$

Step-by-step explanation:

First we have to find the coordinates of the original ordered pairs then we will do the translation.

$Q=(1,3)\\R=(3,-3)\\S=(0,-2)\\T=(-2,1)$

Now we will add 3 to every x value and add a -2 to every y value.

$Q=(1_{+3},3_{+(-2)})\\R=(3_{+3},-3_{+(-2)})\\S=(0_{+3},-2_{+(-2)})\\T=(-2_{+3},1_{+(-2)})$

When you do that you will get the new prime points.

$Q'=(4,1)\\R'=(6,-5)\\S'=(3,-4)\\T'=(1,-1)$

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3 years ago

Otrada [13]

Answer:

Step-by-step explanation:

3 _

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3 years ago

Rewrite (5y)^1/2 as a radical.​