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2 years ago

Y=6x^2-12x-1 minumim function value

Mathematics

2 answers:

kap26 [50]2 years ago

6 0

Answer:

Step-by-step explanation:

ch4aika [34]2 years ago

3 0

Answer:

(−1,5)

Step-by-step explanation:

hope this helpes

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Find the inverse of the following function. Then prove they are inverses of one another.

solmaris [256]

Answer: $\dfrac{x^2+1}{2}$

Step-by-step explanation:

Given

$f(x)=\sqrt{2x-1}$

We can write it as

$\Rightarrow y=\sqrt{2x-1}$

Express x in terms of y

$\Rightarrow y^2=2x-1\\\\\Rightarrow x=\dfrac{y^2+1}{2}$

Replace y be x to get the inverse

$\Rightarrow f^{-1}(x)=\dfrac{x^2+1}{2}$

To prove, it is inverse of f(x). $f(f^{-1}(x))=x$

$\Rightarrow f(f^{-1}(x))=\sqrt{2\times \dfrac{x^2+1}{2}-1}\\\\\Rightarrow f(f^{-1}(x))=\sqrt{x^2+1-1}\\\\\Rightarrow f(f^{-1}(x))=x$

So, they are inverse of each other.

8 0

3 years ago

I am a witch and I'll hex you if you don't know but answer to get the points

Alexeev081 [22]

2+1/3n=8 is the answer, I believe.

4 0

3 years ago

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I need 13-18 pleasseee

Andru [333]

Answer:

wanted points. sorry

Step-by-step explanation:

8 0

2 years ago

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Which graph shows a set of ordered pairs that represent a function?<br><br>Need help

Sveta_85 [38]

Answer:

The third graph, the top right graph

Step-by-step explanation:

A function when determined graphically is a graph that passes the straight line test, which means if there is any two points on the graph which you can plot a vertical straight line going through both of them it is not a function. If 1 x value is equal to 2 y values, it is not a function.

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2 years ago

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What is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

LenKa [72]

${\bold{\red{\huge{\mathbb{QUESTION}}}}}$

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

$\bold{ \red{\star{\blue{GIVEN }}}}$

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

$\bold{\blue{\star{\red{TO \: \: FIND}}}}$

Average cost of 7 articles

$\bold{ \green{ \star{ \orange{FORMULA \: USED}}}}$

$\red{AVERAGE = \frac{TOTAL \: COST}{ NUMBER \: OF\: ARTICLES }}$

$\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}$

$Average \: cost \: of \: 7 \: articles - > \\ \frac{(3 \times 30k) + (12 .5k \times 4)}{7} \\ \frac{90k + 50k}{7} \\ \frac{140k}{7} \\ \blue {Average \: cost \: of \: 7 \: articles - >} \\ 20k$

5 0

2 years ago