Problem 1
<h3>Answer: False</h3>
---------------------------------
Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
===============================================
Problem 2
<h3>Answer: True</h3>
---------------------------------
Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
<span>42.7−<span>(<span>−12.4</span>)
</span></span><span>=<span>42.7−<span>(<span>−12.4</span>)
</span></span></span><span>=<span>42.7+12.4
</span></span><span>=<span>55.1</span></span>
Use the Product Rule: x^ax^b = x^a + b
6x^3 + 1y^2 + 6
Simplify 3 + 1 to 4
6x^4y^2 + 6
Simplify 2 + 6 to 8
<u>= C) 6x^4 y^8</u>
Answer:
Step-by-step explanation:
The table shows how the time it takes a train to travel between two cities depends on its average speed.
function models the time, y, in hours, that it takes the train to travel between the two cities at an average speed of x miles per hour
y represents the time
and x represents the average speed
WE know distance = speed * times
LEts find the distance using the table
distance = 32* 5= 160
40*4= 160
50*3.2 = 160
Time = distance / speed
times is y , distance is 160 and speed is x
Answer:
8304725.2x
Step-by-step explanation:
Hope this helps. Plz give brainliest.
