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Bogdan [553]
4 years ago
6

Given the following polynomial find the maximum possible number of turning points

Mathematics
1 answer:
fenix001 [56]4 years ago
8 0
f'(x)=6x^5+10x^9+9x^8+10x^9=20x^9+9x^8+6x^5

The degree of the derivative is 9, so t<span>he maximum possible number of turning points is 9.</span>
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For the functions f(x) = x^2+ 8x + 2 and g(x) = -5+9, find (f•g)(x)and (f.g)(-1).
Ne4ueva [31]

Answer:  (f·g)(x) = -5x³ - 31x² + 62x + 18

               (f·g)(-1) = -70

(fog)(x) = 25x² - 130x + 155

(fog)(-1) = 310

<u>Step-by-step explanation:</u>

f(x) = x² + 8x + 2          g(x) = -5x + 9

(f·g)(x) = (x² + 8x + 2)(-5x + 9)

          = -5x³ + 9x²

                    - 40x² + 72x

            <u>                    - 10x + 18</u>

          = -5x³ - 31x² + 62x + 18

(f·g)(-1)= -5(-1)³ - 31(-1)² + 62(-1) + 18

         =  -5(-1)  - 31(1)    - 62      + 18

         =    5     -   31      - 62      + 18

         =  -70

****************************************************************************************

(fog)(x) = (-5x + 9)² + 8(-5x + 9) + 2

           = 25x² - 90x + 81

                       - 40x + 72

              <u>                   +   2</u>

           = 25x² - 130x + 155

(fog)(-1) = 25(-1)² - 130(-1) + 155

            =   25    +  130    + 155

            = 310

<em>It wasn't clear if you wanted multiplication or composition so I solved both.</em>

6 0
3 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
3 years ago
1. Use the given translation rule to find the image coordinates. Rule: (x, y) –(x - 4, y + 3) A(4,6) →A') and B(-2,3) -→B'().O A
artcher [175]

We have to translate the coordinates using the given rule.

The given rule is (x-4,y+3)

Now we have to translate the point A(4,6) using the given rule.

Then,

A' is (4-4,6+3)=(0,9)

Now the point B(-2,3) is to be transformed.

Then,

B' is (-2-4,3+3)=(-6,6)

Hence the answer is A'(0,9) and B'(-6,6)

4 0
1 year ago
The sum of two numbers is -25. One number is 101 less than the other. Find the numbers
zlopas [31]

Answer:

-63, 38

Step-by-step explanation:

1st number = x

2nd number = x+101

x+x+101=-25

2x=-126

x=-63

1st number = x = -63

2nd number = x+101 = 38

6 0
3 years ago
Read 2 more answers
How to graph y&gt;1/3x+5
oksano4ka [1.4K]
Slope is:1/3
The y-intercept is (y-intercept:
(0,5)

6 0
3 years ago
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