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AnnZ [28]
4 years ago
9

Evaluate the function: y= -2x + 11 when x = 5.y=_____​

Mathematics
1 answer:
gregori [183]4 years ago
6 0

Answer:

y=1 when x=5

Step-by-step explanation:

-2(5)+11=-10+11=1

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Can someone help me
matrenka [14]
I recommend to use desmos calculator ! It will help !
5 0
3 years ago
Read 2 more answers
A student club holds a meeting. The predicate M(x) denotes whether person x came to the meeting on time. The predicate O(x) refe
Novay_Z [31]

Answer:

a) \exists \, x \in C : O(x) = 0

b) \{ x \in C : O(x) = 1 \} \subseteq \{ x \in C : M(x) = 1 \}

c) \{ x \in C: M(x) = 1 \} = C

d) \{ x \in C : D(x) = 1 \} \, \cup \, \{x \in C : M(x) = 1 \} = C

e) \exists \, x \in C : M(x) = 1 \, \wedge D(x) = 1

f) \exists \, x \in C : O(x) = 1 \, \wedge M(x) = 0

Step-by-step explanation:

  • M(x) = 1 if the person x came to the meeting, and 0 otherwise.
  • O(x) = 1 if the person is an officer of the club and 0 otherwise.
  • D(x) = 1 if the person has paid hid/her club dues and 0 otherwise.

Lets also call C the set given by the members of the club. C is the domain of the functions M, O and D.

a) If someone is not an officer, the there should be at least one value x such that O(x) = 0. This can be expressed by logic expressions this way

\exists \, x \in C : O(x) = 0

b) If all the officers came on time to the meeting, then for a value x such that O(x) = 1, we also have that M(x) = 1. Thus, the set of officers of the Club is contained on the set of persons which came to the meeting on time, this can be written mathematically this way:

\{ x \in C : O(x) = 1 \} \subseteq \{ x \in C : M(x) = 1 \}

c) If everyone was in time for the meeting, then C is equal to the set of persons who came to the meeting on time, or, equivalently, the values x such that M(x) = 1. We can write that this way:

\{ x \in C: M(x) = 1 \} = C

d) If everyone paid their dues or came on time to the meeting, then if we take the set of persons who came to the meeting on time and the set of the persons who paid their dues, then the union of the two sets should be the entire domain C, because otherwise there should be a person that didnt pay nor was it on time. This can be expressed logically this way:

\{ x \in C : D(x) = 1 \} \, \cup \, \{x \in C : M(x) = 1 \} = C

e) If at least one person paid their dues on time and came on time to the meeting, then there should be a value x on C such that M(x) and D(x) are both equal to 1. Therefore

\exists \, x \in C : M(x) = 1 \, \wedge D(x) = 1

f) If there is an officer who did not come on time for the meeting, then there should be a value x in C such that O(x) = 1 (x is an officer), and M(x) = 0. As a result, we have

\exists \, x \in C : O(x) = 1 \, \wedge M(x) = 0

I hope that works for you!

7 0
4 years ago
Diego buys 4.25 pounds of mushrooms. Each pound costs $2.99. Which expression gives the best estimate of the cost of the mushroo
Vadim26 [7]

Answer:

(4)($3)

Step-by-step explanation:

Given parameters:

Quantity of mushroom bought = 4.25pounds

Cost of each mushroom  = $2.99

Unknown:

Best estimate for the cost of the mushroom = ?

Solution:

The cost of the mushroom is:

 Total cost = quantity of mushroom bought x cost of each mushroom

  Total cost  = 4.25 x 2.99

    You can round 4.25 to 4 and 2.99 to 3

                  Or  4 x 3 = $12

8 0
3 years ago
Read 2 more answers
Look at the parallelogram ABCD shown below: The table below shows the steps to prove that if the quadrilateral ABCD is a paralle
riadik2000 [5.3K]

Answer:

The correct option is 1.

Step-by-step explanation:

Statement                                          Reasons

1.   AB is parallel to DC and         Definition of parallelogram

    AD is parallel to BC

2.   angle 1 = angle 2,                   If two parallel lines are cut by a

    angle 3 = angle 4                    transversal then the alternate

                                                      interior angles are congruent

3.    BD = BD                                   Reflexive Property

4.    \triangle ADB\cong \triangle CBD                 ASA postulate

5.   AB = DC, AD = BC                  (CPCTC)

If two angles and the included side of a triangle are congruent to the corresponding angles and side of another triangle then the triangles are congruent by ASA postulate.

According to alternate interior angles theorem, two parallel lines are cut by a transversal then the alternate interior angles are congruent.

Therefore option 1 is correct.

8 0
4 years ago
I don't really understand my math Homework. It's solving problems using equations.
Nataliya [291]
I'll gladly help you, but I can't really read that.
8 0
3 years ago
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