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Lerok [7]
3 years ago
12

Graphing linear equations y+5=-2(x-2)

Mathematics
1 answer:
levacccp [35]3 years ago
6 0
First put the equation in y=mx+b form then plot the b and count off the slope.

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Match each equation with its solution set. Tiles a2 − 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a − 10 = 0 a2 + 5a − 14 = 0 a2 − 5a − 1
sattari [20]
We have that

N 1)
a²<span> − 9a + 14 = 0 
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 9a+20.25)=-14+20.25

Rewrite as perfect squares

(a-4.5)²=6.25--------> (a-4.5)=(+/-)√6.25

a1=4.5+√6.25-----> a1=7

a2=4.5-√6.25-----> a2=2

the solution problem N 1 is the pair {7, 2}


N 2) 

a²<span> + 9a + 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² +9a+20.25)=-14+20.25

Rewrite as perfect squares

(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25

a1=-4.5+√6.25-----> a1=-2

a2=-4.5-√6.25-----> a2=-7

the solution problem N 2 is the pair {-2,-7}

N 3) 

a² + 3a − 10 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 3a)=10

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 3a+2.25)=10+2.25

Rewrite as perfect squares

(a+1.5)²=12.25------> (a+1.5)=(+/-)√12.25

a1=-1.5+√12.25-----> a1=2

a2=-1.5-√12.25-----> a2=-5

the solution problem N 3 is the pair {2, -5}


N 4)

a²<span> + 5a − 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 5a) =14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 5a+6.25) =14+6.25

Rewrite as perfect squares

(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25

a1=-2.5+√20.25-----> a1=2

a2=-2.5-√20.25-----> a2=-7

the solution problem N 4 is the pair {2, -7}


N 5) 

a² − 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 5a)=14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 5a+6.25)=14+6.25

Rewrite as perfect squares

(a-2.5)²=2025--------> (a-2.5)=(+/-)√20.25

a1=2.5+√20.25-----> a1=7

a2=2.5-√20.25-----> a2=-2

the solution problem N 5 is the pair {7, -2}

3 0
3 years ago
Read 2 more answers
What is the area of a 4.2 yard square?
SOVA2 [1]

Answer:

37.8 square feet

Step-by-step explanation:

4 0
3 years ago
1.The growth of a sample of bacteria can be modeled by the function b(t)=100(1.06)t where b is the number of bacteria and t is t
qwelly [4]

Given:

The growth of a sample of bacteria can be modeled by the function

b(t)=100(1.06)^t

where, b is the number of bacteria and t is time in hours.

To find:

The number of total bacteria after 3 hours.

Solution:

We have,

b(t)=100(1.06)^t

Here, b(t) number of total bacteria after t hours.

Substitute t=3 in the given function, to find the number of total bacteria after 3 hours.

b(t)=100(1.06)^3

b(t)=100(1.191016)

b(t)=119.1016&#10;

Therefore, the number of total bacteria after 3 hours is 119.1016.

4 0
2 years ago
Is the student correct?​
Pachacha [2.7K]
Yes the student is correct
6 0
3 years ago
A school is arranging a field trip to the zoo. The school spends 544.95 dollars on passes for 41 students and 4 teachers. The sc
FrozenT [24]

Answer: I believe it is $20.62

Step-by-step explanation: the student passes+ the food was $845.42 divede that by the 41 students.

7 0
2 years ago
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