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3 years ago

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Chemistry

1 answer:

Mademuasel [1]3 years ago

6 0

Answer: Molarity of the solution: 0.12

Molarity of sulfate ion: 0.360

Molarity of aluminum ion: 0.240

Explanation:

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According to cell theory _____.

bulgar [2K]

Answer:

Every single living thing are comprised of cells. Cells are the fundamental units of structure and capacity in living things. New cells are delivered from existing cells.

4 0

4 years ago

A solution is prepared by mixing 2.17 g of an unknown non-electrolyte with 225.0 g of chloroform. The freezing point of the resu

Deffense [45]

Answer:

The molar mass of the unknown non-electrolyte is 64.3 g/mol

Explanation:

Step 1: Data given

Mass of an unknown non-electrolyte = 2.17 grams

Mass of chloroform = 225.0 grams

The freezing point of the resulting solution is –64.2 °C

The freezing point of pure chloroform is – 63.5°C

kf = 4.68°C/m

Step 2: Calculate molality

ΔT = i*kf*m

⇒ ΔT = The freezing point depression = T (pure solvent) − T(solution) = -63.5°C + 64.2 °C = 0.7 °C

⇒i = the van't Hoff factor = non-electrolyte = 1

⇒ kf = the freezing point depression constant = 4.68 °C/m

⇒ m = molality = moles unknown non-electrolyte / mass chloroform

0.7 °C = 1 * 4.68 °C/m * m

m = 0.150 molal

Step 3: Calculate moles unknown non-electrolyte

molality = moles unknown non-electrolyte / mass chloroform

Moles unknown non-electrolyte = 0.150 molal * 0.225 kg

Moles unknown non-electrolyte = 0.03375 moles

Step 4: Calculate molecular mass unknown non-electrolyte

Molar mass = mass / moles

Molar mass = 2.17 grams / 0.03375 moles

Molar mass = 64.3 g/mol

The molar mass of the unknown non-electrolyte is 64.3 g/mol

6 0

3 years ago

The motion of objects can be quite complex. The motion of this frog is an example. Suppose that the frog moves from one lily pad

olga2289 [7]

Answer:

The speed of the frog is 1m per second the velocity is he can turn and jump in a different direction in 1 second the distance is 1m and there is no displacement. I'm pretty sure this is right

Explanation:

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3 years ago

If air has a dry-bulb temperature of 2°C

Allisa [31]

Answer:

The relative humidity is 36%.

Explanation:

Relative humidity is the measure of ratio of actual vapor density to saturated vapor density in a given system. So there are different ways to measure the relative humidity in the atmosphere. One of the common ways is to measure using Psychrometer. In this instrument, two different thermometers are used as measuring device. One of the thermometer measures the humidity in dry air and another in wet air. So the difference of the temperature of dry and wet air bulb will be related to determine the relative humidity percentage. The formula to determine the relative humidity using this method is as below.

$Relative humidity=\frac{(e_{w}-[N*(1+0.00115*T_{w}*(T_{d}-T_{w}))])*100}{e_{d} }$