Answer:
11.08 atm
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 10 atm
Initial temperature (T₁) = 5 °C
Final temperature (T₂) = 35 °C
Final pressure (P₂) =?
Volume = constant
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 5 °C
Initial temperature (T₁) = 5 °C + 273
Initial temperature (T₁) = 278 K
Final temperature (T₂) = 35 °C
Final temperature (T₂) = 35 °C + 273
Final temperature (T₂) = 308 K
Finally, we shall determine the final pressure of the gas as follow:
Initial pressure (P₁) = 10 atm
Initial temperature (T₁) = 278 K
Final temperature (T₂) = 308 K
Final pressure (P₂) =?
P₁/T₁ = P₂/T₂
10/278 = P₂/308
Cross multiply
278 × P₂ = 10 × 308
278 × P₂ = 3080
Divide both side by 278
P₂ = 3080 / 278
P₂ = 11.08 atm
Therefore, the final pressure of the gas is 11.08 atm
