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2 years ago

Can somebody help me please!!

Chemistry

2 answers:

8_murik_8 [283]2 years ago

8 0

Velocity? It goes with the words speed and direction, I don’t really know the context of the question.

wlad13 [49]2 years ago

3 0

Answer: velocity

Explanation: trust me man

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A river with a flow of 50 m3/s discharges into a lake with a volume of 15,000,000 m3. The river has a background pollutant conce

spin [16.1K]

Explanation:

The given data is as follows.

Volume of lake = $15 \times 10^{6} m^{3}$ = $15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}$

Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = $5.6 \times 15 \times 10^{9} mg$

= $84 \times 10^{9}$ mg

= $84 \times 10^{3}$ kg

Flow rate of river is 50 $m^{3} sec^{-1}$

Volume of water in 1 day = $50 \times 10^{3} \times 86400 liter$

= $432 \times 10^{7}$ liter

Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are $2.9792 \times 10^{10} mg$ or $2.9792 \times 10^{4} kg$

Flow rate of sewage = $0.7 m^{3} sec^{-1}$

Volume of sewage water in 1 day = $6048 \times 10^{4}$ liter

Concentration of sewage = 300 mg/L

Total amount of pollutants = $1.8144 \times 10^{10} mg$ or $1.8144 \times 10^{4}kg$

Therefore, total concentration of lake after 1 day = $\frac{131936 \times 10^{6}}{1.938 \times 10^{10}}mg/ l$

= 6.8078 mg/l

$k_{D}$ = 0.2 per day

$L_{o}$ = 6.8078

Hence, $L_{liquid}$ = $L_{o}(1 - e^{-k_{D}t}$

$L_{liquid}$ = $6.8078 (1 - e^{-0.2 \times 1})$

= 1.234 mg/l

Hence, the remaining concentration = (6.8078 - 1.234) mg/l

= 5.6 mg/l

Thus, we can conclude that concentration leaving the lake one day after the pollutant is added is 5.6 mg/l.

5 0

3 years ago

What is physical weathering NOT caused by? (pls i really need help with this!!)

Anarel [89]

Answer:

the changing tempure in rocks causing it to back apart

3 0

2 years ago

The least polar bond is found in a molecule of hi hf hcl hbr

mario62 [17]

Answer:

HI is least polar

Explanation:

5 0

2 years ago

During an endothermic phase change, what happens to the potential energy and the kinetic energy?

antiseptic1488 [7]

During endothermic phase change, the potential energy of the system always increases while the kinetic energy of the system remains constant. The potential energy of the reaction increases because energy is been added to the system from the external environment.

Explanation:

Those are three distinct methods for demonstrating a specific energy condition of an object. They don't affect one another.

"Potential Energy" is a relative term showing a release of possible energy to the environment. If we accept its pattern as the overall energy state of a compound, at that point, an endothermic phase change would infer an increase in "potential" as energy is being added to the compound by the system.

A phase change will display an increase in the kinetic energy at whatever point the compound is transforming from a high density to a low dense phase. The kinetic energy will decrease at whatever point the compound is transforming from a less dense to high dense phase.

4 0

2 years ago

Read 2 more answers

HELP ME PLEASEEE- 8th grade science

icang [17]

Answer:

It's obviously LIGHT ENERGY for me cuz it's from the flashlight..

Explanation:

Hope it helps you..

Your welcome in advance..

(ㆁωㆁ)

3 0

2 years ago