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pshichka [43]
3 years ago
12

2. Solve for b. b (a - 3)

Mathematics
1 answer:
crimeas [40]3 years ago
4 0

Remove parentheses. Which would be a - 3

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When 33 is added to a number the result is 13 more than 5 times the number.
RoseWind [281]
X - the number

x+33=5x+13 \\
x-5x=13-33 \\
-4x=-20 \\
x=\frac{-20}{-4} \\
x=5

The number is 5.
5 0
3 years ago
Read 2 more answers
If thrice a number is subtracted from 100,the difference is 67.Find the number.
Nataly [62]

Answer:

the answer is 167/3

Step-by-step explanation:

8 0
3 years ago
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alexdok [17]

AB and CD are interesting lines

Therefore, the angles formed will be equal (vertically opposite angles).

Hence,

(5x - 10) = (3x + 40)

Now,

5x - 10= 3x + 40

5x - 3x = 40 + 10

2x = 50

x =  \frac{50}{2}

x = 25

3 0
3 years ago
Factor the expression.<br> 20b + 35 =<br> (Factor completely.)
Airida [17]

Answer:

I think it would be 5(4b+7)

Step-by-step explanation:

I divided both terms by 5.

6 0
3 years ago
Drag each tile to the correct box.
rodikova [14]

Answer: C < B < A

<u>Step-by-step explanation:</u>

First, let's evaluate the growth rate of A from [1, 3]

f(x) = 200\bigg(\dfrac{3}{2}\bigg)^1

    = 300

coordinate is (1, 300)

f(x) = 200\bigg(\dfrac{3}{2}\bigg)^3

    = 675

coordinate is (3, 675)

Average growth rate (AGR) is: \dfrac{675-300}{3-1} = \dfrac{375}{2} = 187.5

AGR (A) = 187.5

*************************************************************************************

Next, let's evaluate the growth rate of B from [1, 3]

The coordinates are already provided as (1, 120) and (3, 480)

Average growth rate (AGR) is: \dfrac{480-120}{3-1} = \dfrac{360}{2} = 180

AGR (B) = 180

*************************************************************************************

Lastly, let's evaluate the growth rate of C from [1, 3]

f(x) = 600(1.2)ˣ

f(x) = 600(1.2)¹

     = 720

coordinate is (1, 720)

f(x) = 600(1.2)³

     = 1036.8

coordinate is (3, 1036.8)

Average growth rate (AGR) is: \dfrac{1036.8-720}{3-1} = \dfrac{316.8}{2} = 158.4

AGR (C) = 158.4

8 0
3 years ago
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