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Elden [556K]
3 years ago
13

Express answer in exact form. Show all work for full credit.

Mathematics
2 answers:
konstantin123 [22]3 years ago
7 0

Answer:

1.5 pi in.^2 - 2 & 1/4 sqrt 3 in.^2

Step-by-step explanation:

First, since the hexagon is a regular polygon, then each of the 6 equilateral triangles in the hexagon has all sides of 3 inches. This means that the radius of the circle is equal to 3 inches.  

To find the area of the circle: A = pi * r^2 --> A = 9 pi in.^2.

Next, find the area of the sector: 60o (o = degree sign) divided by 360o --> 60/360 = 1/6 --> 1/6 times area of circle (9 pi) =  

1.5 pi in.^2.

Then, find the area of one of the equilateral triangles by using the formula for the area of an equilateral triangle:  

A = 1/4 * s^2 * sqrt 3 --> A = 1/4 * 3^2 * sqrt 3 --> A = 2 & 1/4 sqrt 3.

Finally, to find the area of the segment, do the area of the sector minus the area of the triangle:  

<u>1.5 pi in.^2 - 2 & 1/4 sqrt 3 in.^2</u> (this is the exact answer; for it to be an approximate answer, you would actually do the equation).

<em>Hope this helps! :)</em>

Mekhanik [1.2K]3 years ago
3 0
The chord length is the same as the radius, so R^2 = 9.
Area = (1/2)(9)(pi/3 - sqrt(3)/2) = (3/4) (2 pi - 3 sqrt(3))
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At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. T
elixir [45]

Answer:

\text{Exact area of the sidewalk}=40 \pi\text{ m}^2

\text{Approximate area of the sidewalk}=125.6\text{ m}^2

Step-by-step explanation:

We have been given that at a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.

To find the area of the side walk we will subtract the area of inner edge of the side walk of lion pen from the area of the outer edge of the lion pen.

\text{Area of circle}=\pi r^2, where r represents radius of the circle.

\text{Exact area of the sidewalk}=\pi*\text{(11 m)}^2-\pi*\text{(9 m)}^2

\text{Exact area of the sidewalk}=\pi*\text{121 m}^2-\pi*\text{81 m}^2

\text{Exact area of the sidewalk}=40 \pi\text{ m}^2

Therefore, the exact area of the side walk is 40 \pi\text{ m}^2

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\text{Approximate area of the sidewalk}=40*3.14\text{ m}^2

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Therefore, the approximate area of the side walk is 125.6\text{ m}^2.

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