Answer:
X = 59
Step-by-step explanation:
2 × 59 = 118
18 + 18 + 59 + 59 = 154
28. Surface Area
This is some sort of house-like model so for every face we see there's a congruent one that's hidden. We'll just double the area we can see.
Area = 2 × ( [14×9 rectangle] + 2[15×9 rectangle]+[triangle base 14, height 6] )
Let's separate the area into the area of the front and the sides; the front will help us for problem 29.
Front = [14×9 rectangle] + [triangle base 14, height 6]
= 14×9 + (1/2)(14)(6) = 14(9 + 3) = 14×12 = 168 sq ft
OneSide = 2[15×9 rectangle] = 30×9 = 270 sq ft
Surface Area = 2(168 + 270) = 876 sq ft
Answer: D) 876 sq ft
29. Volume of an extruded shape is area of the base, here the front, times the height, here 15 feet.
Volume = 168 * 15 = 2520 cubic ft
Answer: D) 2520 cubic ft
<span>The answer to this question would be: 5 days
In this question, there are two kinds of rent pricing and you are asked to find the number of days when both of them will charge the same price.
From the description, you can get an equation of each price which would look like this(x=number of day rent):
cost1= 110 + 46x
cost2= 70 + 54x
Then, the days when the price same would be:
cost1 = cost2
</span>110 + 46x= 70+54x
110-70= 54x - 46x
40= 8x
x=5
<u>Given</u>:
Given that O is the center of the circle.
The radius of the circle is 3 m.
The measure of ∠AOB is 30°
We need to determine the length of the major arc ACB
<u>Measure of major ∠AOB:</u>
The measure of major angle AOB can be determined by subtracting 360° and 30°
Thus, we have;
Thus, the measure of major angle is 330°
<u>Length of the major arc ACB:</u>
The length of the major arc ACB can be determined using the formula,
<u></u>
<u></u>
Substituting r = 3 and 
, we get;
Thus, the length of the major arc ACB is 5.5π m
To find the inverse interchange the variables and solve for y
