<h3>
Answer: 104 square feet</h3>
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Explanation:
The horizontal pieces are the parallel bases
b1 = 17 and b2 = 9
The height is always perpendicular to the base, so h = 8
The 4 ft portion won't be used in the next section, so we can ignore it.
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Plug the values mentioned into the trapezoid area formula below. Simplify.
A = h*(b1+b2)/2
A = 8*(17+9)/2
A = 8*26/2
A = 8*13
A = 104 square feet
We can abbreviate "square feet" into "sq ft" or "ft^2" without quotes.
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As another approach, you can split the trapezoid into 2 triangles and a rectangle in between. Then find the area of each small piece, and add up those smaller areas to get the final answer. You should get 104. If you go with this approach, then you will use the 4 ft portion to help find the horizontal length of the triangle on the right.
Answer:
D . 20ft2
Step-by-step explanation:
Answer:
3/8
Step-by-step explanation:
divide out the 4's and you are left with 3/8
Answer:
13.695 m
Step-by-step explanation:
The assumption made here is that the boat/water interface is essentially frictionless, so that the center of mass of the system remains in the same place as the occupant of the boat moves around.
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We can find the sum of the moments of boat and child about the pier end:
(46 kg)(7.6 m) + (80 kg)((7.6 +9.6/2) m) = 1341.6 kg·m
After the child moves, the center of mass of boat and child is presumed to remain in the same place. If x is the new distance from the pier to the child, the sum of moments is now ...
46x +80(x-4.8)* = 1341.6
126x -384 = 1341.6
x = (1341.6 +384)/126 = 13 73/105 ≈ 13.695 . . . meters
The child is about 13.695 meters from the pier when she reaches the far end of the boat.
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* The center of mass of the boat alone is half its length closer to the pier than is the child, so is located at x-4.8 meters.
Answer:
20 minutes
Step-by-step explanation:
x is 0 in the graph and y is 20
so 20 is your answer if 0 is x
