<h3>
Answer: Choice C 
</h3>
The open circle means we do not include the endpoint, hence the use of a greater than symbol. If we were to include the endpoint, then we'd have greater than or equal to. We can rule out choice B due to this reasoning.
The ray pointing to the right indicates we are talking about x values larger than 5, so we can rule out choice A and conclude the answer is C.
Side note: The notation 
is saying "x is a real number"
Answer:
Step-by-step explanation:
28x^3 = 2 * 2 * 7 * x * x * x
16x^2Y^2 = 2 * 2 * 2 * 2 * x * x * y *y
GCF = 2 * 2 * x *x = 4x^2
Circle which are in both
Answer:
A. 
Step-by-step explanation:
We have the expression
![log_{3} (\sqrt[5]{x} *y)](https://tex.z-dn.net/?f=log_%7B3%7D%20%28%5Csqrt%5B5%5D%7Bx%7D%20%2Ay%29)
As these two values are being multiplied, we can separate the two and the sum of them will be equal to the multiplied version
![log_{3}\sqrt[5]{x} +log_{3}y](https://tex.z-dn.net/?f=log_%7B3%7D%5Csqrt%5B5%5D%7Bx%7D%20%2Blog_%7B3%7Dy)
The ![\sqrt[5]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%7D)
can be rewritten as 
. This allows us to use the exponent rule. This means that it can be written as
Answer:
Area of a semi circle is 1/2πr²
r = radius
Area = 1/2 × π × 18²
= 162π
= 508.94km²
Hope this helps.
Answer:
The figure is attached down
Step-by-step explanation:
To graph a line you must have its equation
The form of the linear equation is y = m x + b, where
- m is its slope
- b is the y-intercept (y at x = 0)
∵ The slope of the line is 
∴ y = x + b
- To find b substitute x and y in the equation by the coordinates
of a point on the line
∵ The line passing through point (-5 , -4)
∴ x = -5 and y = -4
∵ -4 = (-5) + b
∴ -4 = 
+ b
- Subtract from both sides
∴ 
= b
∴ y = x - 
To draw the line substitute x by any two values and find their ys
∵ x = -2
∴ y = (-2) -
∴ y = -6
∴ The line passing through point (-2 , -6)
∵ x = 1
∴ y = (1) -
∴ y = -8
∴ The line passing through point (1 , -8)
∵ x = 4
∴ y = (4) -
∴ y = -10
∴ The line passing through point (4 , -10)
Now we can make a table to draw the line
→ x : -5 : -2 : 1 : 4
→ y : -4 : -6 : -8 : -10
Plot the points on the graph paper and draw the line
<em>Look to the attached graph</em>
