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3 years ago

Benito wants to buy a car.he is linking a to models model a is 7 1/8 ft wide. Model b is 93 inches wide.

1 answer:

6 0

First find out how many cm at in an foot then convert it over to cm or feet. Then compare. The larger number is the wider car.

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CATNUMATICAL Reason Quantitatively Rachel, Timothy, and Robyn each make

valkas [14]

Answer:

See explanation

Step-by-step explanation:

The question is incomplete, as the dimension of each prism is not given.

So, I will give a general explanation.

From the question, we understand each prism.

So, to get the new volume; we simply add up the volume of each prism.

For instance (we want to make assumptions)

Rachel

$Length = 4; Width = 3; Height = 4$

Timothy

$Length = 6; Width = 3; Height = 4$

Robyn

$Length = 4; Width = 8; Height = 3$

So, we have:

$Volume = Length * Width * Height$

For each, we have:

$Rachel =4* 3* 4 =48$

$Timothy= 6* 3* 4 = 72$

$Robyn = 4* 8* 3 = 96$

The volume of the new

$Volume = 48 + 72 + 96$

$Volume = 216$

The dimension of new prism.

Using the assumed values, we have:

$Length = 4; Width = 3; Height = 4$

$Length = 6; Width = 3; Height = 4$

$Length = 4; Width = 8; Height = 3$

Now, we consider the measure of the sides

Sides with the same length will form a new side.

Side 1

$Length =4$ --- Rachel

$Height = 4$ ---- Timothy

$Length = 4$ --- Robyn

The above lengths have the same measure. So, one of the sides of the new prism will assume the value of this length.

So:

$Length = 4$ -- for the new prism

Side 2

$Width =3$

$Width = 3$

$Height = 3$

The above lengths have the same measure. So, one of the sides of the new prism will assume the value of this length.

So:

$Width = 3$ -- for the new prism

Side 2

$Height = 4$

$Length = 6$

$Width =8$

For this, we simply add up each length.

So, we have:

$Height = 4 + 6 + 8$

$Height = 18$ --- for the new prism

So, the new dimension is:

$Length = 4$

$Length = 6$

$Height = 18$

$Volume = 4 * 3 * 18$

$Volume = 216$

5 0

2 years ago

F(x)= -2x^3 +14x -8 g(x)= 2x+6

melamori03 [73]

Answer:

F(2x+6)=-16x^3-144x^3-404x-356

Step-by-step explanation:

6 0

2 years ago

identify the graph of 9x^2-25y^2=225 for t(0 5) and write an equation of the translated or rotated graph in general form

tamaranim1 [39]

ANSWER

The required equation is:

$9 {x}^{2} - 25{y}^{2} + 250y - 85 0=0$

EXPLANATION

The given equation is

$9 {x}^{2} - 25 {y}^{2} = 225$

Dividing through by 225 we obtain;

$\frac{ {x}^{2} }{25} - \frac{ {y}^{2} }{9} = 1$

This is a hyperbola that has it's centre at the origin.

If this hyperbola is translated so that its center is now at (0,5).

Then its equation becomes:

$\frac{ {(x - 0)}^{2} }{25} - \frac{ {(y - 5)}^{2} }{9} = 1$

We multiply through by 225 to get;

$9 {x}^{2} - 25( {y - 5})^{2} = 225$

We now expand to get;

$9 {x}^{2} - 25( {y}^{2} - 10y + 25 )= 225$

$9 {x}^{2} - 25{y}^{2} + 250y - 6 25 = 225$

The equation of the hyperbola in general form is

$9 {x}^{2} - 25{y}^{2} + 250y - 85 0=0$

5 0

3 years ago

Read 2 more answers

Question:

prohojiy [21]

Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').)
Write this in cases:
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant.
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0.
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b.
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function.
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x).
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.)
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have.
I hope this helps!

4 0

3 years ago

Which characteristics do the functions have in common? Select two options.

dlinn [17]

Range and y intercept are two characteristics they have in common

8 0

3 years ago