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Lesechka [4]
3 years ago
5

Sandy has 18 roses, 9 daisies, and 45 tulips. She wants to arrange all the followers in bouquets. Each bouquet has the same numb

er of flowers and same type of flower. What is the greatest number of flowers that could be in a bouquet?
Mathematics
1 answer:
uranmaximum [27]3 years ago
8 0

Answer:

Greatest number of flowers in a bouquet = 9 flowers

Step-by-step explanation:

Total no. of roses = 18

Total no. of daisies = 9

Total no. of tulips = 45

To find the greatest no. of flowers that can be arranged in the bouquet such that there are same number of flowers and same type of flowers in the bouquet, we will take the H.CF (highest common factor) of 18,9,45

H.C.F of 18,9,45 = 9

Hence, the greatest number no. of flowers that can be arranged in the bouquet = 9 flowers.

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A company manufactures three types of cabinets. It makes 110 cabinets each week. In the first week, the sum of the number of typ
miss Akunina [59]

Answer:

  • In the first week, the number of type-1 cabinets produced was 15,
  • the number of type-2 cabinets produced was 30,
  • the number of type-3 cabinets produced was 65.

Step-by-step explanation:

If we let a, b, c represent the numbers of type-1, type-2, and type-3 cabinets produced in the first week, respectively, we can write three equations in these unknowns:

  • a + b + c = 110 . . . . . total cabinets for the first week
  • a + 2b - c = 10 . . . . relationship of quantities in the first week
  • 3a +0b +c = 110 . . . . total cabinets in the second week

It can be convenient to let a machine solver find the solution to this set of equations. Most graphing calculators can handle it, along with several web sites.

__

Solving by hand, we can subtract the second equation from twice the first. This gives ...

  2(a +b +c) -(a +2b -c) - 2(110) -(10)

  a +3c = 210 . . . . simplify

Subtracting this from 3 times the third equation gives ...

  3(3a +c) -(a +3c) = 3(110) -(210)

  8a = 120 . . . . . simplify

  a = 15 . . . . . . . divide by 8

Using this in the third equation of the original set, we have ...

  3·15 +c = 110

  c = 65 . . . . . . subtract 45

Then, in the first equation, we get ...

  15 + b + 65 = 110

  b = 30 . . . . . . . subtract 80

The solution is (type-1, type-2, type-3) = (15, 30, 65) for the first week.

4 0
4 years ago
Read 2 more answers
You play tennis with your friend every week. From all of the past games, you know that each game is independent and you estimate
Murrr4er [49]

Answer:

120%

Step-by-step explanation:

8 0
3 years ago
ga political candidate has asked you to conduct a poll to determine what percentage of people support her. if the candidate only
Vedmedyk [2.9K]

Answer: 151

Step-by-step explanation:

if prior population proportion is unknown , then the formula is used to find the sample size :

n=0.25(\frac{z_{\alpha/2}}{E})^2

, where z_{\alpha/2} = Two tailed critical value for significance level of \alpha.

E = Margin of error.

Given : margin of error = 8%= .08

For 95% confidence level , two tailed critical value = 1.96

Now, the required sample size :

n=0.25(\frac{1.96}{0.08})^2\\\\=0.25(24.5)^2\\\\=150.0625\approx151

Hence, the size of the sample needed = 151.

7 0
3 years ago
A fountain on a lake sprays water in a parabolic arch modeled by the equation
NikAS [45]
Hello,

Answer B (2.0017868263...feet)

We must foind the intersection of the line and the parabola:

- \dfrac{4}{10} x^2+3x= \dfrac{22}{49}x+ \dfrac{818}{490}\\
...\\
196x^2-1250x+818=0\\

x= \dfrac{1250- \sqrt{921188} }{392}\approx0.7403433860\\

y=-0.4*0.74034...^2+3*0.74034...\approx2.0017868263...


5 0
3 years ago
M is midpoint of AB. AM = 11x - 9, and BM = 7x + 35. <br> 1. Find X<br> 2. Find AM<br> 3. Find BM
Sphinxa [80]

Answer:

if m is midpoint then AM=BM

11X-9=7x+35

4x=44

x=11

AM=11×11-9 =121-9=112

BM=112

8 0
3 years ago
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